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fomenos
3 years ago
9

Please don't answer if you don't know.

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
7 0
Since they are vertical angles, they are congruent:

2x + 2 = 3x - 52

Solving:

54 = x

Hope this helps!
sladkih [1.3K]3 years ago
4 0
2x + 2 = 3x - 52

2x - 3x = -2 - 52

- x = - 54

x = 54


hope this helps
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At an ice cream parlor, ice cream cones cost $1.10 and sundaes cost $2.35. One day, the receipts for a total of 172 cones and su
antoniya [11.8K]
Let assume
X for ice cream cones
Y for sundaes
X+Y=172
X=172-Y……..*
1.10X+2.35Y=294.20
Substitute * in the above equation
1.10(172-Y)+2.35Y=294.20
189.2-1.10Y+2.35Y=294.20
1.25Y=294.20-189.2
1.25Y=105 divide both sides by 1.25
Y=84
The substitute Y value in * equation
X=172-84
X=88
Therefore
88 ice cream cones and 84 sundaes were sold!!
4 0
3 years ago
Use two different methods to find an explain the formula for the area of a trapezoid that has parallel sides of length a and B a
evablogger [386]

Answer:

Formula of Trapezoid:

A = (a + b) × h / 2

The formula can be derived in different ways. for now, we have discussed two ways:

1. By using the formula of a triangle

2. By dividing into different sections

Step-by-step explanation:

1. By using the formula of a triangle

One of the ways to explain a formula for an area of a trapezoid using a formula for a triangle can be as follows.

Assume a trapezoid PQRS with lower base SR and upper base PQ (they are parallel) and sides PS and QR.

The image is attached below.

Connect vertices P and R with a diagonal.

Consider triangle ΔPQR as having a base PQ and an altitude from vertex R down to point M on base PQ (RM⊥PQ).

Its area is

S1=\frac{1}{2} *PQ*RM

Consider triangle ΔPRS as having a base SR and an altitude from vertex P up to point N on-base SR (PN⊥SR).

Its area is

S2=\frac{1}{2} *SR*PN

Altitudes RM and PN are equal and constitute the distance between two parallel bases PQ and SR.

They both are equal to the altitude of the trapezoid h.

Therefore, we can represent areas of our two triangles as

S1=\frac{1}{2}*PQ*h

S2=\frac{1}{2}*SR*h

Adding them together, we get the area of the whole trapezoid:

S=S1+S2=\frac{1}{2} (PQ+SR)h,

which is usually represented in words as "half-sum of the bases times the altitude".

2. By dividing into different sections

Trapezoid PQRS is shown below, with PQ parallel to RS.

Figure 1 - Trapezoid PQRS with PQ parallel to RS(image is attached below.)

We are going to derive the area of a trapezoid by dividing it into different sections.

If we drop another line from Q, then we will have two altitudes namely PT and QU.

Figure 2 - Trapezoid PQRS divided into two triangles and a rectangle. (image is attached below.)

From Figure 2, it is clear that Area of PQRS = Area of PST + Area of PQUT + Area of QRU. We have learned that the area of a triangle is the product of its base and altitude divided by 2, and the area of a rectangle is the product of its length and width. Hence, we can easily compute the area of PQRS. It is clear that

=> A_{PQRS} = (\frac{ah}{2}) + b_{1}h + \frac{ch}{2}

Simplifying, we have

=>A= \frac{ah+2b_{1+C} }{2}

Factoring we have,

=> A_{PQRS} = (a+ 2b_{1} + c)\frac{h}{2}  \\= > {(a+ b_{1} + c) + b_{1} }\frac{h}{2}

 But, a+ b_{1} + c  is equal to b_{2}, the longer base of our trapezoid.

Hence, A_{PQRS}= (b_{1} + b_{2} )\frac{h}{2}

We have discussed two ways by which we can derive area of a trapezoid.

Read to know more about Trapezoid

brainly.com/question/4758162?referrer=searchResults

#SPJ10

5 0
2 years ago
Determine the number of lines of symmetry for the figure
Ganezh [65]
10 is the right answer
8 0
3 years ago
What is 77,543 rounded to the nearest ten?
Montano1993 [528]
77,543 rounded to the nearest ten is 77,540
6 0
3 years ago
Read 2 more answers
A cube-shaped box has a volume of 1000 cubic inches. How tall is the box?
Bezzdna [24]

Answer:

10 inches

Step-by-step explanation:

the box is 1000 cubic inches in volume, and 10×10×10 is 1000

The side lengths are each 10 inches tall

The box is 10 inches tall, wide, and long

4 0
3 years ago
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