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marissa [1.9K]
3 years ago
9

A new computer workstation has been installed in a small office. the user of the workstation can print a document using a networ

k printer on the lan, but cannot access the internet. what is a possible cause of the problem?
Computers and Technology
1 answer:
ICE Princess25 [194]3 years ago
3 0
The printer is setup as a local printer therefore it does not need access to internet to access the local network printer. Once the new workstation is given access to the terminal server used for the printer, it will not need to connect on the internet to print. Now, if the workstation is not able to access the internet it could be potentially due to incorrect configuration of DNS to the workstation or actual issue is within the ISP.
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In Mandatory Access Control sensitivity labels attached to object contain what information?
larisa86 [58]

Answer:b)The item’s classification and category set

Explanation: Mandatory access control(MAC) is the security component in the computer system. It is regarding the controlling the access of the operating system by the administrator.The accessing is made limited by the MAC according to the sensitivity of the data .

The authorization for user to access the system is based on this sensitivity level known sensitivity label. The objects contain the information regarding the classification and categories or level of items. Thus, the correct option is option(b).

7 0
3 years ago
Which one of these choices best describes what exec() does:a) It replaces the current process with a new oneb) It executes a new
Dimas [21]

Answer:

Option b It executes a new process, which runs at the same time as the parent

Explanation:

The exec is one of the Java Runtime methods which is used to create a new process and run it as an separate process. Exec method executes the string command that we place inside the bracket. For example,

Process proc = Runtime.getRuntime().exec("Notepad.exe");

The statement above offers a convenient way to open the another computer software such as Notepad when running the program.  

3 0
3 years ago
How to calculate 100MB at 56 Kbps to transfer time?
Gelneren [198K]
1MB=1000 kb 

\frac{100*1000Kb}{56Kb/s} ≈ 1748,71 seconds 


ransform in kilobyte and share knowing transfer time :)
3 0
3 years ago
Which of the following is among the ComScore Ad Metrix Reports?
IceJOKER [234]
I think it is d but not exactly sure
6 0
2 years ago
Given positive integer numinsects, write a while loop that prints that number doubled without reaching 100. follow each number w
ELEN [110]
Please provide the language you're using when you ask for programming help, otherwise you aren't going to get the answer that you are looking for.

Here it is in Java, and I'm assuming the number is given via user input? Otherwise, just remove the user input function and replace the integer with a value of your choice. Note, that this isn't the full code; only what is relevant to the question.


public static void main(String[] args) {
    int num = numInput(10);
    printDoubles(num, 100);  // You can create a user input function for
                                             // maxValue if you wanted to.
}

/**
 * Receives user input between 0 and the absolute value of maxInput.
 * @param maxInput The largest absolute value that can be input.
 */
private static int numInput(int maxInput) {
    Scanner sc = new Scanner(System.in);

    maxInput = Math.abs(maxInput);

    int num = 0;
    while (!(num > 0 && num <= maxInput)) {
        num = sc.nextInt();

        if (!(num > 0 && num <= maxInput)) {
            System.out.println("Input too small or too large");
        }
    }

    return num;
}

/**
 * Continues to print out num doubled until maxValue is reached.
 * @param num The number to be printed.
 * @param maxValue The maximum value (not including in which num can                                       be doubled to.
 */
private static void printDoubles(int num, int maxValue) {
    if (num >= maxValue) {
        System.out.println("No output.");
    }

    while (true) {
        if (num >= maxValue) {
            break;
        }

        if (num < maxValue) {
            System.out.print(num + " ");
        }

            num *= 2;
    }

    System.out.println();
}

8 0
3 years ago
Read 2 more answers
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