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3 years ago

Define Turbo C++ and how is the use of Turbo C++.?

Computers and Technology

1 answer:

anyanavicka [17]3 years ago

6 0

Answer:

Turbo C++ is a Compiler and Integrated development Environment (IDE) and Computer language

Explanation:

Turbo C++ is a IDE which is used for writing the programs.
This editor is used to create the source file, compile and run the source file and then execute it

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(1) Prompt the user to enter two words and a number, storing each into separate variables. Then, output those three values on a

Sergeu [11.5K]

Answer:

import java.util.Scanner;

public class num3 {

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

System.out.println("Enter Favorite color");

String word1 = in.next();

System.out.println("Enter Pet's name");

String word2 = in.next();

System.out.println("Enter a number");

int num = in.nextInt();

//Point One

System.out.println("You entered: "+word1+" "+word2+

" "+num);

//Point Two

String passwordOne = word1+"_"+word2;

String passwordTwo = num+word1+num;

System.out.println("First password: "+passwordOne);

System.out.println("Second password: "+passwordTwo);

//Point Three

int len_passwrdOne = passwordOne.length();

int len_passwrdTwo = passwordTwo.length();

System.out.println("Number of characters in "+passwordOne+" :" +

" "+len_passwrdOne);

System.out.println("Number of characters in "+passwordTwo+" :" +

" "+len_passwrdTwo);

}

Explanation:

This question is solved using java programming language
The scanner class is used to receive the three variables (Two string and one integer)
Once the values have been received and stored in the respective variables (word1, word2 and num), Use different string concatenation to get the desired output as required by the question.
String concatenation in Java is acheived with the plus (+) operator.

3 0

3 years ago

Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server

sattari [20]

Answer:

The smallest number of servers required is 3 servers

<em />

Explanation:

Given

$Reliability = 99.98\%$

$Individual Servers = 95\%$

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

$p = 95\%\\$

It should be noted that probabilities always add up to 1;

So,

$p + q = 1$ '

Subtract p from both sides

$p - p + q = 1 - p$

$q = 1 - p$

Substitute $p = 95\%\\$

$q = 1 - 95\%$

Convert % to fraction

$q = 1 - \frac{95}{100}$

Convert fraction to decimal

$q = 1 - 0.95$

$q = 0.05$

------------------------------------------------------------------------------------------------

<em>To get an expression for one server</em>

The probabilities of 1 servers having 99.98% reliability is as follows;

$p = 99.98\%$

Recall that probabilities always add up to 1;

So,

$p + q = 1$

Subtract q from both sides

$p + q - q = 1 - q$

$p = 1 - q$

So,

$p = 1 - q = 99.98\%$

$1 - q = 99.98\%$

Let the number of servers be represented with n

The above expression becomes

$1 - q^n = 99.98\%$

Convert percent to fraction

$1 - q^n = \frac{9998}{10000}$

Convert fraction to decimal

$1 - q^n = 0.9998$

Add $q^n$ to both sides

$1 - q^n + q^n= 0.9998 + q^n$

$1 = 0.9998 + q^n$

Subtract 0.9998 from both sides

$1 - 0.9998 = 0.9998 - 0.9998 + q^n$

$1 - 0.9998 = q^n$

$0.0002 = q^n$

Recall that $q = 0.05$

So, the expression becomes

$0.0002 = 0.05^n$

Take Log of both sides

$Log(0.0002) = Log(0.05^n)$

From laws of logarithm $Loga^b = bLoga$

So,

$Log(0.0002) = Log(0.05^n)$ becomes

$Log(0.0002) = nLog(0.05)$

Divide both sides by $Log0.05$

$\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}$

$\frac{Log(0.0002)}{Log(0.05)} = n$

$n = \frac{Log(0.0002)}{Log(0.05)}$

$n = \frac{-3.69897000434}{-1.30102999566}$

$n = 2.84310893421$

$n = 3 (Approximated)$

<em>Hence, the smallest number of servers required is 3 servers</em>

6 0

3 years ago

The entirety of a packet at one Layer becoming the payload section at another is know as?

MA_775_DIABLO [31]

The answer to the question is: encapsulation

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3 years ago

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1. What is the Internet?

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A place to watch daisy Taylor vids

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3 years ago

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Does the wireless signal between the cell phones require matter to travel from one phone to another?

mrs_skeptik [129]

Mobile phones transmit and receive signals using electromagnetic waves, that is, wireless signal are electromagnetic waves which can travel through a vacuum, they do not need a medium or matter.

<h3>What are electromagnetic waves?</h3>

They are generated by electrical and magnetic particles moving at the same time (oscillating).

<h3>Characteristics of electromagnetic waves</h3>

Network waves are electromagnetic waves.

A mobile phone has coverage when it receives electromagnetic waves from at least one base station.

They do not necessarily require a material medium for their propagation.

Therefore, we can conclude that electromagnetic waves are those that do not need a material medium to propagate and include, among others, radio, television and telephone waves.

Learn more about electromagnetic waves here: brainly.com/question/13803241

3 0

2 years ago