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natali 33 [55]
3 years ago
14

Subtract. −9 1/3−(−1 1/3) Enter your answer, in simplest form, in the box.

Mathematics
2 answers:
zimovet [89]3 years ago
8 0

Answer:

Answer is 8 .

Step-by-step explanation:

Given:  -9\frac{1}{3} -(-1\frac{1}{3}) .

To find: Subtract  in simplest form .

Solution: We have given that  

-9\frac{1}{3} -(-1\frac{1}{3})  .

Convert the mixed fraction into improper fraction

\frac{-28}{3} -(\frac{-4}{3}) .

Now taking the denominator common

\frac{-28+4}{3}).

\frac{-24}{3}).

    =  8

Therefore , answer is 8 .

lbvjy [14]3 years ago
4 0
-9 1/3 - (- 1 1/3) =
-9 1/3 + 1 1/3 =
-8 <==
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25% discount for AED 4000
Lostsunrise [7]

Answer:

The 25% discount on AED 4000 will be: 1000 AED

Step-by-step explanation:

Given

  • The amount = 4000
  • Discount = 25%

In order to determine a 25% discount on the amount AED 4000, all we need means is to multiply 25/100 or (0.25) by 4000.

i.e

Discount amount = 25% of 4000

                             = 25/100 × 4000

                             = 0.25 × 4000

                             = 1000 AED

Thus, the 25% discount on AED 4000 will be: 1000 AED

5 0
3 years ago
Refer to the figure at the right. If
asambeis [7]

Answer:m∠1 = 145°

m∠2 = 35°

m∠3 = 35°

m∠4 = 145°

m∠5 = 145°

m∠6 = 35°

m∠7 = 35°

m∠8 = 145°

Step-by-step explanation:

3 0
3 years ago
A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past
Vadim26 [7]

Answer:

We conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

Step-by-step explanation:

We are given that a particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8000.

From the 28 tires surveyed, the mean lifespan was 46,500 miles with a standard deviation of 9800 miles.

<u><em>Let </em></u>\mu<u><em> = average miles for deluxe tires</em></u>

So, Null Hypothesis, H_0 : \mu \geq 50,000 miles   {means that deluxe tire averages at least 50,000 miles before it needs to be replaced}

Alternate Hypothesis, H_A : \mu < 50,000 miles    {means that deluxe tire averages less than 50,000 miles before it needs to be replaced}

The test statistics that will be used here is <u>One-sample z test statistics</u> as we know about population standard deviation;

                                  T.S.  = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean lifespan = 46,500 miles

            \sigma = population standard deviation = 8000 miles

            n = sample of tires = 28

So, <u><em>test statistics</em></u>  =  \frac{46,500-50,000}{\frac{8000}{\sqrt{28} } }

                               =  -2.315

The value of the test statistics is -2.315.

Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is less than the critical value of z as -2.315 < -1.6449, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

4 0
3 years ago
Dillion divided a 3 1/3 pound bag of pears among his 5 friends. How many pounds of pears does did each friend revive?
IgorLugansk [536]

Your answer is .6 repeating or 2/3 per person.

8 0
3 years ago
Side of the equation to se<br>2. n+ 5 = -2​
Gekata [30.6K]

Answer:

n= 7

Step-by-step explanation:

First subtract by 5, it gives you 0 subtract 2 more. You get -2, there for n=7

7 0
3 years ago
Read 2 more answers
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