Question

Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 76.676.6 Mbps. The complete list of 50 data speeds has a mean of x overbarxequals=17.9517.95 Mbps and a standard deviation of sequals=23.3923.39 Mbps. a. What is the difference betweenâcarrier's highest data speed and the mean of all 50 dataâ speeds? b. How many standard deviations is thatâ [the difference found in partâ (a)]? c. Convert theâ carrier's highest data speed to a z score. d. If we consider data speeds that convert to z scores between minusâ2 and 2 to be neither significantly low nor significantlyâ high, is theâ carrier's highest data speedâsignificant?

Answer 1

Answer:

Step-by-step explanation:

Researchers measured the data speeds for a particular smartphone carrier at 50 airports.

The highest speed measured was 76.6 Mbps.

n= 50

X[bar]= 17.95

S= 23.39

a. What is the difference between​ the carrier's highest data speed and the mean of all 50 data​ speeds?

If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps

b. How many standard deviations is that​ [the difference found in part​ (a)]?

To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation

Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations

c. Convert the​ carrier's highest data speed to a z score.

The value is X= 76.6

Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51

d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly​ high, is the​ carrier's highest data speed​ significant?

The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.

I hope it helps!