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3 years ago

-7x² - 6x +9 and 3x²-x+7

Mathematics

1 answer:

Alex17521 [72]3 years ago

5 0

Answer:

For -7x^2 - 6x + 9: $-\frac{3+6\sqrt{2} }{7}$ $-\frac{3-6\sqrt{2} }{7}$

For 3x^2 -x + 7: $\frac{x+i\sqrt{83} }{6}$ $\frac{x-i\sqrt{83} }{6}$

Step-by-step explanation:

Find the zeros using the quadratic formula. Solution attatched. I apologize for poor handwriting. Also, there should be a negative sign before the answer to the first expression in the solution.

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You are designing a rectangular garden. the garden will be enclosed by fencing on three sides and by a house on the fourth side.

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Suppose the dimensions of the rectangle is x by y and let the side enclosed by a house be one of the sides measuring x, then the sides that is to be enclosed are two sides measuring y and one side measuring x.

Thus, the length of fencing needed is given by

P = x + 2y

The area of the rectangle is given by xy,

i.e.

$xy = 288 \\ \\ \\ \\ \Rightarrow y= \frac{288}{x}$

Substituting for y into the equation for the length of fencing needed, we have

$P=x+2\left( \frac{288}{x} \right)=x+ \frac{576}{x}$

For the amount of fencing to be minimum, then

$\frac{dP}{dx} =0 \\ \\ \Rightarrow1- \frac{576}{x^2} =0 \\ \\ \Rightarrow \frac{576}{x^2} =1 \\ \\ \Rightarrow x^2=576 \\ \\ \Rightarrow x=\sqrt{576}=24$

Now, recall that

$y= \frac{288}{x} = \frac{288}{24} =12$

Thus, the length of fencing needed is given by

P = x + 2y = 24 + 2(12) = 24 + 24 = 48.

Therefore, 48 feets of fencing is needed to enclose the garden.

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3 years ago

Please help what is q-75=50

kogti [31]

You have to add 75 to Both sides and 50+75= 125 So q=125. Hope this helped!

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4 years ago

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It is a cylinder.........

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marta [7]

Answer:

Step-by-step explanation:

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Substituting x = 0 in this function, we get:

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skelet666 [1.2K]

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