Positive integer factors of 100:
1, 2, 4, 5, 10, 20, 25, 50, 100
Now find if they are a multiple of 2 or 3.
2, 4, 10, 20, 50, 100
That is 6 factors.
Answer:(-2,0) and (3,0)
Step-by-step explanation:im not sure if its correct but it should be
Direct variation is represented by the equation y = k × x and inverse variation is represented by y = k/x
Table 1:
y = k × x
30 = k × 5
30 = 5k
k = 30/5
k = 6
So,
<em>y = 30 </em>
<em>y = 30 k = 6</em>
<em>y = 30 k = 6x = 5</em>
<em>y = 30 k = 6x = 5Equation: y = 6x</em>
y = k × x
y = 10 × 8
y = 80
So,
<em>y = 80 </em>
<em>y = 80 k = 10</em>
<em>y = 80 k = 10x = 8</em>
<em>y = 80 k = 10x = 8Equation: y = 10x</em>
y = 3x
18 = 3x
x = 18/3
x = 6
So,
<em>y = 18</em>
<em>y = 18k = 3</em>
<em>y = 18k = 3x = 6</em>
<em>y = 18k = 3x = 6Equation: y = 3x</em>
y = 2x²
72 = 2x²
x² = 72/2
x² = 36
x = √36
x = 6
So,
<em>y = 72</em>
<em>y = 72k = 2</em>
<em>y = 72k = 2x = 6</em>
<em>y = 72k = 2x = 6Equation: y = 2x²</em>
Table 2:
y = k/x
5 = k/6
5 × 6 = k
30 = k
So,
<em>y = 5</em>
<em>y = 5k = 30</em>
<em>y = 5k = 30x = 6</em>
<em>y = 5k = 30x = 6Equation: y = 30/x</em>
y = k/x
y = 36/4
y = 9
So,
<em>y = 9</em>
<em>y = 9k = 36</em>
<em>y = 9k = 36x = 4</em>
<em>y = 9k = 36x = 4Equation: y = 36/x</em>
y = 60/x
20 = 60/x
20x = 60
x = 60/20
x = 3
So,
<em>y = 20</em>
<em>y = 20k = 60</em>
<em>y = 20k = 60x = 3</em>
<em>y = 20k = 60x = 3Equation: y = 60/x</em>
y = 24/x
y = 24/12
y = 2
So,
<em>y = 2</em>
<em>y = 2k = 24</em>
<em>y = 2k = 24x = 12</em>
<em>y = 2k = 24x = 12Equation: y = 24/x</em>
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Answer:
C
Step-by-step explanation:
If I'm not mistaken, she wants to ride atleast 85 miles per week. If you add up all of the values from going to and from the school, you would get 62.5 miles. So for it to add up to 85 miles, she would have to atleast do 9 trips around the park.
These numbers I believe do not matter however, all you need to do is put in C for greater than or equal to 85.