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Rzqust [24]
2 years ago
11

What value of u is a solution to this equation? u–4=5 u = 8 or u = 9

Mathematics
2 answers:
Archy [21]2 years ago
5 0
U=9
9-5=4
i hope this helps <3
muminat2 years ago
3 0
U=9 because you add 4 to both sides of the equation and 5+4=9
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A circular garden has a circumference of
omeli [17]

This solution to this problem is predicated on the fact that the circumference is just: 2\pir. A straight line going through the center of the garden would actually be the diameter, which is well known to be two times the radius of the circle, so we can say that the circumference is just:

d\pi

So, solving for both the radius and the diameter gives us:

d\pi=8xy^2\pi\\ d=8xy^2\\ \\ 2\pi r=8xy^2\pi\\ r=4xy^2

So, the length of thes traight path that goes through the center of the guardain is just 8xy^2, and we can use the radius for the next part of the problem.

The area of a circle is \pi r^2, which means we can just plug in the radius and find our area:

A=\pi r^2 \implies \\ A=\pi (4xy^2)^2\implies \\ A= 16\pi x^2y^4

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6 0
3 years ago
Carl tells his friend Logan about a new music download service. Carl says that if you download x collections per month, your mon
harkovskaia [24]
D.Both Carl and Logan are incorrect
3 0
3 years ago
Read 2 more answers
the length of a rectangle is two feet greater then twice its width if the primeter is 25 find the width
Mademuasel [1]

Answer:

Step-by-step explanation:

Perimeter is simply length + width. They gave us that the length is 2 feet plus 2 times the width:

25=(2w+2)+W

Subtract 2 from both sides to get 23 = 2w + w

Combine like terms to get 23 = 3w

Divide by 3 to get w=7 \frac{2}3} feet

7 0
3 years ago
You run one lap around a mile track every 8 minutes. Your friend runs around the same track every 10 minutes. You both start at
Ber [7]

Answer:

Step-by-step explanation:

first runs n+1 laps

and second runs n laps in the same time.

so (n+1)8=10n

10n=8n+8

10n-8n=8

2n=8

n=8/2=4

one lap=1 mile

4 laps=4 miles

4+1=5 laps=5 miles.

first runs 5 miles whereas second runs=4 miles.

3 0
3 years ago
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T F IfA and B are similar matrices, then AT=BT
muminat

Answer:

Step-by-step explanation:

We know that for two similar matrices A and B exists an invertible matrix P for which

[tex]B = P^{-1} AP[/tex]

∴ B^{T} = (P^{-1})^{T} A^{T} P^{T} \\

Also P^{-1}P = I\\

and (P^{-1})^{T} = (P^{T})^{-1}

∴(P^{-1})^{T}P^{T} = I

so, B^{T} = (P^{-1})^{T} A^{T} P^{T} = (P^{T})^{-1}A^{T} P^{T}\\B^{T} = A^{T} I\\B^{T} = A^{T}

7 0
3 years ago
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