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WITCHER [35]
4 years ago
13

Subtract polynomials

Mathematics
1 answer:
ziro4ka [17]4 years ago
6 0

Answer: For this, you need to equal the equations to each other, then combine like terms and subtract from both sides :).

Step-by-step explanation:

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Locate and label each set of points on the coordinate plane. Describe similarities of the ordered pairs in each set,
Leya [2.2K]

Answer:

THX FOR FREE POINT

Step-by-step explanation:

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3 years ago
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An investment that you bought ____ and sold for ___ made a profit
Irina-Kira [14]
A. 400, 500
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3 years ago
Which of the following are identities? check all that apply.
Feliz [49]

Answer: (a), (b), (c), and (d)

Step-by-step explanation:

Check the options

(a)\\\Rightarrow [\sin x+\cos x]^2=\sin ^2x+\cos ^2x+2\sin x\cos x\\\Rightarrow [\sin x+\cos x]^2=1+2\sin x\cos x\\\Rightarrow \Rightarrow [\sin x+\cos x]^2=1+\sin 2x

(b)\\\Rightarrow \sin (6x)=\sin 2(3x)\\\Rightarrow \sin 2(3x)=2\sin (3x)\cos (3x)

(c)\\\Rightarrow \dfrac{\sin 3x}{\sin x\cos x}=\dfrac{3\sin x-4\sin ^3x}{\sin x\cos x}\\\\\Rightarrow 3\sec x-4\sin ^2x\sec x\\\Rightarrow 3\sec x-4[1-\cos ^2x]\sec x\\\Rightarrow  3\sec x-4\sec x+4\cos x\\\Rightarrow 4\cos x-\sec x

(d)\\\Rightarrow \dfrac{\sin 3x-\sin x}{\cos 3x+\cos x}=\dfrac{2\cos [\frac{3x+x}{2}] \sin [\frac{3x-x}{2}]}{2\cos [\frac{3x+x}{2}]\cos [\frac{3x-x}{2}]}\\\\\Rightarrow \dfrac{2\cos 2x\sin x}{2\cos 2x\cos x}=\dfrac{\sin x}{\cos x}\\\\\Rightarrow \tan x

Thus, all the identities are correct.

4 0
3 years ago
PLEASE HELPPP!!! I"M DESPRITE!!!
Anton [14]

Answer:

The answer is no, it cannot be 11 inches

Step-by-step explanation:

If the width is 5 inches and the area must be less than 55 square inches,

5 x 11 = 55

55 = 55

It is asking if

55 < 55

6 0
4 years ago
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Zina [86]

Option A would be the best strategy here.

4 0
3 years ago
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