Answer:
2x^2 +2x-4
——————
2x^2-4x+2
Factor out 2 from the expression
2(x^2+x-2)
—————-
2(x^2-2x+1)
Write x as a difference
2(x^2x-x-2)
—————-
2(x^2-2x+1)
Use a^2-2ab+b^2=(ab)^2
2(x^2x-x-2)
—————-
2(x-1)^2
Reduce the fraction with 2
x^2x-x-2
—————-
(x-1)^2
Factor out x from the expression
X*(x^2)-x-2
—————-
(x-1)^2
Factor out negative sign from the expression
X*(x+2)-(x-2)
—————-
(x-1)^2
Factor out x+2 from the expression
(x+2)(x-1)
—————-
(x-1)^2
Simplify the expression
x+2
——
x-1
Pretty sure x=-24.5 did the math. Check my answer before you submit anything
Answer:
Option (B)
Step-by-step explanation:
From the graph attached,
There are two functions 'f' and 'g' graphed.
Value of the function 'h' at x = 1,
y = h(1) = 0
Now we know g[h(1)] = g(0) [By substituting the value of h(1) = 0]
Therefore, value of the function 'g' at x = 0,
y = g(0) = -5 [y-intercept at x = 0]
Option (B) will be the correct option.
Answer:
(f + g)(x) = I2x + 1I + 1 ⇒ C
Step-by-step explanation:
Let us solve the question
∵ f(x) = I2x + 1I + 3
∵ g(x) = -2
→ We need to find (f + g)(x), which means add the two functions
∵ (f + g)(x) = f(x) + g(x)
→ Substitute the right side of each function on the right side
∴ (f + g)(x) = I2x + 1I + 3 + (-2)
→ Remember (+)(-) = (-)
∴ (f + g)(x) = I2x + 1I + 3 - 2
→ Add the like terms in the right side
∵ (f + g)(x) = I2x + 1I + (3 - 2)
∴ (f + g)(x) = I2x + 1I + 1
