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lora16 [44]
3 years ago
11

4y+12=6y+12 solve the equation

Mathematics
2 answers:
vampirchik [111]3 years ago
5 0

y=0

hope this helps

Marizza181 [45]3 years ago
4 0

Answer:

y = 0

Step-by-step explanation:


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Beth made wristbands and belts for a craft sale. She sold 30 of these items. Each wristband sold for $5.50. Each belt sold at $8
baherus [9]

<u>✿</u><u>Answer:</u>

  • Both sold 18 wristbands and 12 belts

✂----------------------

Let, number of wristbands = x

number of belts = y

x+y=30  ➞ x~5.5

5.50x+8.75y=204 x1

5.50x+5.5y=165\\5.5x+8.75y=204\\---------\\-3.25y=-39

y=-39/3.25

y=12

x=30-12=18

So, Both~ sold ~18 ~wristbands ~and ~12~ belts.

❄❄❄❄❄❄

<h3>hope it helps...</h3><h3>have a great day!!</h3>
5 0
2 years ago
1. Andrew ran a marathon in about 1.56 x 10^4 s. (a) Write Andrews time in standard notation. (b) Evelyn ran a marathon in 4 h a
romanna [79]

Answer:

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  • (b)  Evelyn

Step-by-step explanation:

(a) 1.56×10^4 = 1.56×10000 = 15,600

(b) There are 3600 seconds in an hour, so Andrew's time was

  15600 s/(3600 s/h) = 13/3 h = 4 1/3 h

1/3 hour is 20 minutes, so Evelyn's time of 4:16 is shorter than Andrew's time of 4:20.

7 0
3 years ago
Solve for x in terms of r, s and t : s=2x+t/r
Anna007 [38]

For this case we have the following equation:

s = \frac {2x + t} {r}

We must clear the value of the variable "x" as a function of r, s and t:

If we multiply by "r" on both sides of the equation we have:

rs =2x + t

If we subtract "t" on both sides of the equation we have:

rs-t = 2x

If we divide by "2" on both sides of the equation we have:

x = \frac {rs-t} {2}

Thus, the value of the variable "x" is:

x = \frac {rs-t} {2}

Answer:

x = \frac {rs-t} {2}

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3 years ago
Convert: 6 cubic centimeters to fluid Ounces.<br> O 0.203<br> O 0.000203<br> 02.03<br> 0.00203
ladessa [460]

I think the correct answer is A because 6 cubic centimeters to fluid ounces equals 0.202884, but if you round it you get 0.203

Mark Brainliest if correct

6 0
3 years ago
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The United States increased its global influence.
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