348 fluid ounces = 2/3 of the water.
So, 1/3 of the jar would be = 348 ÷ 2 = 174.
Three-thirds of the jar = (1/3) × 3 = 174 × 3 = <em>522</em><em></em>.
- The jar can hold 522 fluid ounces of water.
<em>I hope this helps! If it did, please mark me BRAINLIEST!!! (So that others can know my answer was the right answer, if they need the right answer)</em>
Answer: 5,260
Step-by-step explanation:
So the question here is 45% of WHAT number (x) = 2,367
Setup as a fraction
45/100 = 2,367/X
Cross multiply
45X=236,700
Divide 45X by 45 to get X alone
Divide the other side too bc what you do to one side, you have to do to the other.
236,700/45=
5,260
Check your answer
45/100=2367/5260
I believe the answer would be 768 tiles
First, do 5 = 12 = 17.
Look at the numbers you have.
What numbers can make 17?
You basically add ().
You add the () between 2 x 6 (2x6) to show that you do that first.
Then, once you get the answer for that, add 5.
5+(2x6) = 17.
I hope this helps! :D
Answer:
Hello,
Step-by-step explanation:
![I=\dfrac{Area}{4} =\int\limits^4_0 {\sqrt{16-x^2} } \, dx \\\\Let\ say\ x=4*sin(t),\ dx=4*cos(t) dt\\\\\displaystyle I=\int\limits^\frac{\pi }{2} _0 {4*\sqrt{1-sin^2(t)} }*4*cos(t) \, dt \\\\=16*\int\limits^\frac{\pi }{2} _0 {cos^2(t)} \, dt \\\\=16*\int\limits^\frac{\pi }{2} _0 {\frac{1-cos(2t)}{2}} \, dt \\\\=8*[t]^\frac{\pi }{2} _0-[\frac{sin(2t)}{2} ]^\frac{\pi }{2} _0\\\\=4\pi -0\\\\=4\pi\\\\\boxed{Area=4*I=16\pi}\\](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7BArea%7D%7B4%7D%20%3D%5Cint%5Climits%5E4_0%20%7B%5Csqrt%7B16-x%5E2%7D%20%7D%20%5C%2C%20dx%20%5C%5C%5C%5CLet%5C%20say%5C%20x%3D4%2Asin%28t%29%2C%5C%20dx%3D4%2Acos%28t%29%20dt%5C%5C%5C%5C%5Cdisplaystyle%20I%3D%5Cint%5Climits%5E%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20_0%20%7B4%2A%5Csqrt%7B1-sin%5E2%28t%29%7D%20%7D%2A4%2Acos%28t%29%20%5C%2C%20dt%20%5C%5C%5C%5C%3D16%2A%5Cint%5Climits%5E%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20_0%20%7Bcos%5E2%28t%29%7D%20%5C%2C%20dt%20%5C%5C%5C%5C%3D16%2A%5Cint%5Climits%5E%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20_0%20%7B%5Cfrac%7B1-cos%282t%29%7D%7B2%7D%7D%20%5C%2C%20dt%20%5C%5C%5C%5C%3D8%2A%5Bt%5D%5E%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20_0-%5B%5Cfrac%7Bsin%282t%29%7D%7B2%7D%20%5D%5E%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20_0%5C%5C%5C%5C%3D4%5Cpi%20-0%5C%5C%5C%5C%3D4%5Cpi%5C%5C%5C%5C%5Cboxed%7BArea%3D4%2AI%3D16%5Cpi%7D%5C%5C)
