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Arada [10]
4 years ago
15

An object moves along the x-axis, its position at each time t> 0 given by \"x(t) = 81/2*t^2-3/4*t^4\" Determine the time inte

rval(s), if any, during which the object slows down.
Mathematics
1 answer:
Tamiku [17]4 years ago
3 0
You can say an object slow down when the acceleration is negative which can be observed on a negative slope during the graph of acceleration, from a position equation lets derive 2 times to attain the acceleration equation

<span>x(t) = 81/2*t^2-3/4*t^4
V(t) = 81X - 3t^3
A(t) = 81 - 9t^2

</span>81 - 9t^2 < 0<span>
t^2 > 9
-3 > t > 3


</span>
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