Question

Determine whether y2=3x+1 is a function.

Answer 1

Answer: it is not a function

Step-by-step explanation:

Given :

$y^{2}$ = 3x + 1

The first thing is to make y the subject of the formula, that means we will take the square root of both sides

y = $\sqrt{3x + 1}$

since y =  $\sqrt{3x + 1}$ , the the value of y could be positive or negative.

For example , $\sqrt{4}$ = ± 2 , since -2 x -2 will also give + 4

For y =  $\sqrt{3x + 1}$ to be a function , there must be a unique value for y for each value of x , but this is not the case as y could be positive or negative for a single value of x , so it is not a function.