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djyliett [7]
3 years ago
14

Why are animals important to an ecosystem?

Biology
1 answer:
solmaris [256]3 years ago
7 0
A. They produce carbon dioxide<span> for food it includes both so it would be more correct

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Instead of swimming alone, many types of fish swim together in groups, or schools. When grouped together, the fish may appear to
Mamont248 [21]

The answer to your question is cooperation.

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3 years ago
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Students are studying the rate of yeast fermentation under different conditions. Glucose is a monosaccharide. Sucrose is a
Akimi4 [234]

Answer:

The correct option is B. Fermentation would occur at a similar rate to that of glucose.

Explanation:

Fermentation can be described as a process in which alcohol is released by using sugars. In fruit juices, fructose is present mainly to get the sweetness. It is used as a substitute for glucose because fructose is more sweeter than glucose. Both fructose and glucose are monosaccharides with the formula C6H12O6. The only difference is in the arrangement of molecules in the atoms of these compounds. Hence, the rate of fermentation would be same for these two sugars.

8 0
3 years ago
Give some examples of biodiversity you find in your ecosystem.
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3 years ago
Systemic fungal infections (e.g. Candida and Cryptococcus) and tuberculosis (Mycobacterium) are on the rise. One of the reasons
miss Akunina [59]

Answer:

a) the molecules can be found in the picture below

b) (i) isocitrate lyase ( isocitrate to glyoxylate)

   (ii) malate synthase (glyoxylate to malate)

c)  Glyoxylate cycle do no exist in animals

Explanation:

b) in the glyoxylate cycle isocitrate lyase helps in conversion of  isocitrate to glyoxylate. Also, helps in conversion of glyoxylate to malate by using malate synthase.

c)   Glyoxylate cycle do no exist in animals, it only exist in plants and bacteria. This is because they can produce glucose from acetyl-CoA in required amounts.They have the ability to change acetyl-CoA from fat into glucose. But in animals, this mechanism is not possible.

6 0
3 years ago
In chickens, comb shape is determined by two independent genes (R and P). A walnut comb is produced when at least one dominant a
Aleksandr [31]

Answer:

Option B, Rr pp × rr Pp

Explanation:

Given

Walnut Comb is produces when  one dominant allele R is present at one gene locus and at least one dominant allele P is present at a second gene locus - R* P*

Rose Comb - at least one dominant allele is present at the first locus and two recessive alleles are present at the second locus - R* pp

Pea comb - two recessive alleles are present at the first locus and at least one dominant allele is present at the second  - rr P*

Single comb - two recessive alleles are present at the first and the second locus  - rrpp

Parent are rose combed and pea combed

For being rose genotype must be R* pp

and for being pea combed genotype must be rr P*

Rr pp x rr Pp

will  produce

Walnut comb  with genotype Rr Pp

Single comb  with genotype rrpp

and pea comb  with genotype rrPp

Hence, option B is correct

8 0
3 years ago
Read 2 more answers
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