Answer:
The correct option is B. Fermentation would occur at a similar rate to that of glucose.
Explanation:
Fermentation can be described as a process in which alcohol is released by using sugars. In fruit juices, fructose is present mainly to get the sweetness. It is used as a substitute for glucose because fructose is more sweeter than glucose. Both fructose and glucose are monosaccharides with the formula C6H12O6. The only difference is in the arrangement of molecules in the atoms of these compounds. Hence, the rate of fermentation would be same for these two sugars.
Most people recognize biodiversity by species—a group of individual living organisms that can interbreed. Examples of species include blue whales, white-tailed deer, white pine trees, sunflowers, and microscopic bacteria that can't even be seen by the naked eye.
Answer:
a) the molecules can be found in the picture below
b) (i) isocitrate lyase ( isocitrate to glyoxylate)
(ii) malate synthase (glyoxylate to malate)
c) Glyoxylate cycle do no exist in animals
Explanation:
b) in the glyoxylate cycle isocitrate lyase helps in conversion of isocitrate to glyoxylate. Also, helps in conversion of glyoxylate to malate by using malate synthase.
c) Glyoxylate cycle do no exist in animals, it only exist in plants and bacteria. This is because they can produce glucose from acetyl-CoA in required amounts.They have the ability to change acetyl-CoA from fat into glucose. But in animals, this mechanism is not possible.
Answer:
Option B, Rr pp × rr Pp
Explanation:
Given
Walnut Comb is produces when one dominant allele R is present at one gene locus and at least one dominant allele P is present at a second gene locus - R* P*
Rose Comb - at least one dominant allele is present at the first locus and two recessive alleles are present at the second locus - R* pp
Pea comb - two recessive alleles are present at the first locus and at least one dominant allele is present at the second - rr P*
Single comb - two recessive alleles are present at the first and the second locus - rrpp
Parent are rose combed and pea combed
For being rose genotype must be R* pp
and for being pea combed genotype must be rr P*
Rr pp x rr Pp
will produce
Walnut comb with genotype Rr Pp
Single comb with genotype rrpp
and pea comb with genotype rrPp
Hence, option B is correct
