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andriy [413]
3 years ago
8

What is 32/100 equal to?

Mathematics
2 answers:
Romashka [77]3 years ago
7 0

Answer:

32%

Step-by-step explanation:

Usimov [2.4K]3 years ago
3 0

Answer:

.32 or 32%

Step-by-step explanation:

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Help plssss and thank you
dimaraw [331]

Answer:

y=\frac{1}{4}x +3

Step-by-step explanation:

slope (rise over run) choose 2 points that are easy to figure out. Count up and over to get the slope

(0,3) and (4,4)

3 to 4 is 1

0 to 4 is 4

slope is 1/4

y intercept is b- so +3

y=y=\frac{1}{4} x+3

5 0
3 years ago
Solve for w. 9w-4/4=5w-6/7+6​
ELEN [110]

Answer:

w=\frac{1}{16}

Step-by-step explanation:

\frac{9w-4}{4} =\frac{5w-6}{7+6}

9w-1=\frac{5w-6}{13}

9w-1+1=\frac{5w-6}{13}+1

9w=\frac{5w-6}{13}+1<u />

13 × 9w = 13 × \frac{5w-6}{13}+1

117w = 5w - 6 + 13

117w = 5w + 7

117w - 5w = 5w - 5w + 7

112w = 7

112w ÷ 112 = 7 ÷ 112

w=\frac{1}{16}

5 0
3 years ago
Let the universal set, s, have 66 elements. a and b are subsets of s. set a contains 19 elements and set b contains 34 elements.
Otrada [13]

The cardinality of the union between two sets is given by

N(A\cup B) = N(A) + N(B) - N(A \cap B)

In fact, if an element is in both A and B, it is counted in both N(A) and N(B), so we're counting it twice. By subtracting the cardinality of the interserction, we're taking back one of these "extra-counted" element, and the count is correct. In your case, the numbers are

N(A \cup B) = 19+34-10 = 43

This means that the two sets cover, without repetitions, 43 of the 66 elements in the sets. So, there are

66-43 = 23

elements which are in neither A nor B

5 0
3 years ago
There is 5/6 of an apple pie left from dinner. Tomorrow, victor plans to eat 1/6 of the pie that was left. How much of the whole
myrzilka [38]
5/6 - 1/6 = 4/6 reduced to 2/3
4 0
3 years ago
Read 2 more answers
The sum of a number and three is less than nineteen less than the number
Nataliya [291]
The answer to the solution is X+3<19-x.

6 0
4 years ago
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