In my opinion the new coordinates are
A' (-3, -5)
If the discriminant(b^2-4ac) is rational, then the quadratic is rational.
~ThePirc
Sue is correct.
When you plug in the values for x you find that Mark's answer for y should be 32/3 and Sue's answer for y should be 8 which is the answer she has.
Answer:
C) -8cos 3xsin x
Step-by-step explanation:
To express -4(sin4x - sin2x) as a product, we use the formula sinA - sinB = 2cos[(A + B)/2]sin[(A - B)/2.
Comparing sin4x - sin2x with sinA - sinB, A = 4x and B = 2x.
Substituting these into the equation, we have
sin4x - sin2x = 2cos[(4x + 2x)/2]sin[(4x - 2x)/2
sin4x - sin2 x = 2cos[6x/2]sin[2x/2]
sin4x - sin2x = 2cos3xsinx
So, -4(sin4x - sin2x) = -4(2cos3xsinx) = -8cos3xsinx
So, -4(sin4x - sin2x) = -8cos3xsinx
Thus, the answer is C
1) the slope of a line is m in the equation y=mx+b, in this case m isn’t there because m=1 so the slope is 1
2) the slope of a perpendicular line of this would be the reciprocal which is -1
