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inna [77]
3 years ago
8

m∠AOB = 6x + 5, m∠BOC = 4x - 2, m∠AOC = 8x + 21

Mathematics
1 answer:
AnnZ [28]3 years ago
6 0
The sum of angle AOB and angle BOC is equal tot he angle of AOC so

6x+5 +4x-2 = 8x+21

10x+3=8x+21

Subtract three and 8x from both sides

2x=18

Divide by two

x=9

Hope this helped!
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7a ( 1,1)

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Eva8 [605]
We know that
case 1)
Applying the law of sines
a/Sin A=b/Sin B
A=56°
a=12
b=14
so
a*Sin B=b*Sin A----> Sin B=b*Sin A/a---> Sin B=14*Sin 56°/12
Sin B=0.9672
B=arc sin (0.9672)------> B=75.29°-----> B=75.3°

find angle C
A+B+C=180°-----> C=180-(A+B)----> C=180-(56+75.3)----> C=48.7°

find c
a/Sin A=c/Sin C----> c=a*Sin C/Sin A----> c=12*Sin 48.7°/Sin 56°)
c=10.87-----> c=10.9

the answer Part 1)
the dimensions of the triangle N 1
are
a=12  A=56°
b=14  B=75.3°
c=10.9  C=48.7°

case 2) 
A=56°
a=12
b=14
B=180-75.3----> B=104.7°

find angle C
A+B+C=180°-----> C=180-(A+B)----> C=180-(56+104.7)----> C=19.3°

find c
a/Sin A=c/Sin C----> c=a*Sin C/Sin A----> c=12*Sin 19.3°/Sin 56°)
c=4.78-----> c=4.8

the answer Part 2)
the dimensions of the triangle N 2
are
a=12  A=56°
b=14  B=104.7°
c=4.8    C=19.3°
3 0
3 years ago
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