All categories

2 years ago

What is the gcf of 45 and 75

Mathematics

2 answers:

kherson [118]2 years ago

5 0

Hi,

Answer: The Greatest Common Factor (GCF) of 45 and 75 is 3 and 5.

<u>My work:</u> To find the Greatest Common Factor (GCF) Divide and simplify both numbers until you find your match or your GCF.

I Hope I Helped!

blondinia [14]2 years ago

5 0

15 is the gcf because 45/15=3 and 75/15=5

You might be interested in

Determine rather each equation is there not a equation. Write yes or no. if yes write equation in standard form. -2x-3=y

abruzzese [7]

I don't know about how to put that in standard form, but an equation has to have an equals sign... So, that would be an equation.

8 0

3 years ago

Mr. Wells runs a telecommunications company. While going through the company's project records, he found that there were 8 engin

Allisa [31]

There are 12 project managers that are employed by Mr. Wells

<h3>Further explanation</h3>

Solving linear equation mean calculating the unknown variable from the equation.

Let the linear equation : y = mx + c

If we draw the above equation on Cartesian Coordinates , it will be a straight line with :

<em>m → gradient of the line</em>

<em>( 0 , c ) → y - intercept</em>

Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :

$\large {\boxed{m = \frac{y_2 - y_1}{x_2 - x_1}}}$

If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :

$\large {\boxed{y - y_1 = m ( x - x_1 )}}$

<em>Let us tackle the problem!</em>

$\texttt{ }$

This problem is about Directly Proportional.

<em>There were 8 engineers under every team leader.</em>

$\texttt{1 Team Leader} \rightarrow \texttt{8 engineers}$

$\texttt{15 Team Leader} \rightarrow 15 \times \texttt{8 engineers} = \boxed{\texttt{120 engineers}}$

$\texttt{ }$

<em>There were 5 project managers for every 50 engineers.</em>

$\texttt{50 engineers} \rightarrow \texttt{5 project managers}$

$\texttt{120 engineers} \rightarrow (120 \div 50) \times \texttt{5 project managers} = \boxed{\texttt{12 project managers}}$

$\texttt{ }$

<h3>Learn more</h3>

Infinite Number of Solutions : brainly.com/question/5450548
System of Equations : brainly.com/question/1995493
System of Linear equations : brainly.com/question/3291576

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

7 0

3 years ago

PLEASE HELP QUICK, I need to know the answer.

Marysya12 [62]

The equivalent expression is $7^{2}$ .

We have the following expression -

$\frac{7^{-3} }{7^{-5} }$

We have to find its equivalent value.

<h3>What is the equivalent expression of the following expression-</h3>

$f(x, y) =\frac{A^{x} }{A^{y} }$

In order to divide two exponents with same base, we use the 'Quotient property of exponents.

The equivalent expression can be written as -

f(x, y) = $A^{x} A^{-y} = A^{x-y}$

In the question given we have -

$\frac{7^{-3} }{7^{-5} }$

Using the property discussed above -

$7^{-3}\;7^{5}$ = $7^{-3+5}$ = $7^{2}$

Hence, the equivalent expression is $7^{2}$ .

To solve more questions on exponents, visit the link below -

brainly.com/question/17173276

#SPJ5

3 0

2 years ago

Read 2 more answers

I want a way to solve this question

AURORKA [14]

Answer:

Step-by-step explanation:

Using the Cosine rule to find ∠ A

cosA = $\frac{b^2+c^2-a^2}{2bc}$

= $\frac{5.1^2+5.7^2-7.3^2}{2(5.1)(5.7)}$

= $\frac{26.01+32.49-53.29}{58.14}$

= $\frac{5.21}{58.14}$ , then

∠ A = $cos^{-1}$ ( $\frac{5.21}{58.14}$ ) ≈ 84.9° ( to 1 dec. place )

5 0

2 years ago

Help me on this one please

shepuryov [24]

Answer:

The equation is set up wrong

Step-by-step explanation:

$9^{2} +b^{2} =15^{2}$

3 0

2 years ago