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JulsSmile [24]
3 years ago
11

The area of a parallelogram is the same as the area of a square. The base of the parallelogram is twice the length of its height

. The side of the square is 2 less than the height of the parallelogram
Area of a parallelogram: a = base • height
Area of a square: a = (side)2
1. variable h = parallelogram height
2. square area + parallelogram area
3. equation: (h – 2)2 + (2h • h)
Analyze Jasper’s work. What was his mistake?
The variable should be the length of the square.
The areas of the square and parallelogram are equal.
The area of a square is 4(h – 2).
The area of a parallelogram is 2h + h.
Mathematics
2 answers:
Allisa [31]3 years ago
5 0

Answer:

(B)

The areas of the square and parallelogram are equal

olya-2409 [2.1K]3 years ago
5 0

Answer:

b

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=2x%5E2%2B5x%2B3%3D0" id="TexFormula1" title="2x^2+5x+3=0" alt="2x^2+5x+3=0" align="absmiddle"
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Answer:

x=-\frac{3}{2},-1

Step-by-step explanation:

2x^2+5x+3=0

Split the second term (5x) into two terms. Multiply the coefficient of the first term (2) by the constant term (3):

2*3=6

Find which two numbers add up to 5 and multiply into 6:

3+2=5\\3*2=6\\3,2

Split 5x as the sum of 3x and 2x:

2x^2+3x+2x+3

Now factor out a common term for the first 2 terms:

2x^2+3x\\x(2x+3)

And do the same for the last 2 terms:

2x+3\\1(2x+3)

Re-insert:

x(2x+3)+1(2x+3)=0

Factor out the common term 2x+3 and insert the values in front of the parentheses (x and 1):

(2x+3)(x+1)=0

Separate the parentheses and equal them to 0. Solve for x:

2x+3=0\\2x+3-3=0-3\\2x=-3\\\\\frac{2x}{2}=\frac{-3}{2}\\\\  x=-\frac{3}{2}

and

x+1=0\\x+1-1=0-1\\x=-1

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