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Artemon [7]
3 years ago
10

Determine where the function is linear or quadratic. Identify the Quadratic, Linear and constant Terms

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0
Hello,

A
quadratic trem= 4x²-4x²=0
linear terms=4x-x=3x
Constant term =1*(-1)=-1

y
quadratic trem= -15x²
linear terms=-15x -18x=-33x
Constant term =3*(-6)=-18

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Grace [21]

Answer:

Solve the equation for y by finding a, b, and c

of the quadratic then applying the quadratic formula.

Exact Form:

y = 3,−9/2

Decimal Form:

y = 3,−4.5

Mixed Number Form:

y = 3,− 4 1/2

Step-by-step explanation:

branliest pls

7 0
2 years ago
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What’s the value of the ratio 21:45
hichkok12 [17]

Answer:

im not sure but I think it's 1.5

3 0
3 years ago
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Find the area shaded <br> PLEASE HELPPPPP
Ulleksa [173]
3+6-7=2
2x5/2=5(1)
6x5/2=15(2)
The area shaded: (1)+(2) => 5+15=20
Answer: 20
5 0
2 years ago
This is confusing<br> (2x+y)^2−(x−2y)^2
Iteru [2.4K]

Answer:

{(2x + y)}^{2}  -  {(x - 2y)}^{2}

<  {(x + y)}^{2}  =  {x}^{2}  + 2xy +  {y}^{2}  >

<  {(x - y)}^{2}  =  {x}^{2}  - 2xy +  {y}^{2}  >

{(2x)}^{2}  + 2(2x)(y) +  {(y)}^{2}  -  {(x)}^{2}  - 2(x)(2y) +  {(2y)}^{2}

{4x}^{2}  + 4xy +  {y}^{2}  -  {x}^{2}  - 4xy +  {4y}^{2}

{4x}^{2}   -  {x}^{2}  +  {4y}^{2}  +  {y}^{2}

= {3x}^{2}  +  {5y}^{2}

5 0
3 years ago
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Can someone please help me with this ASAP!! (will mark as brainliest if correct)
sattari [20]

Answer:

P = 6x-2

x = 14

Step-by-step explanation:

To find the perimeter, we add the sides

P = 4x-8 + 3-2x + 5x+3

Combine like terms

P = 4x-3x+5x  -8+3+3

  = 6x -2

Now we know the perimeter

82 = 6x-2

Add 2 to each side

82+2 = 6x-2+2

84 = 6x

Divide each side by 6

84/6 = 6x/6

14=x

6 0
3 years ago
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