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3 years ago

How do you solve this step by step?

Mathematics

2 answers:

kolezko [41]3 years ago

5 0

Answer:

Step-by-step explanation:

Evaluate x^2 + 2 x^2 + 3 x^2 + 4 x^2 where x = 3:

x^2 + 2 x^2 + 3 x^2 + 4 x^2 = 3^2 + 2×3^2 + 3×3^2 + 4×3^2

3^2 = 9:

3^2 + 2×9 + 3×3^2 + 4×3^2

3^2 = 9:

3^2 + 2×9 + 3×9 + 4×3^2

3^2 = 9:

3^2 + 2×9 + 3×9 + 4×9

3^2 = 9:

9 + 2×9 + 3×9 + 4×9

2×9 = 18:

9 + 18 + 3×9 + 4×9

3×9 = 27:

9 + 18 + 27 + 4×9

4×9 = 36:

9 + 18 + 27 + 36

| 3 |

| 3 | 6

| 2 | 7

| 1 | 8

+ | | 9

| 9 | 0:

Answer: 90

san4es73 [151]3 years ago

5 0

Answer:

270

Step-by-step explanation:

first you would put a 3 in all of the X

3^2+2(3)^2+3(3)^2+4(3)^2

9+36+81+144

270

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a sign says that the price marked on all music equipment is 30% off the original price you buy an electric guitar for sale price

prohojiy [21]

The original price is $450.

Step-by-step explanation:

Step 1:

Given details, Discount%, D% = 30 and Selling Price, SP = $315

Step 2:

Write down formula for calculating the Original Price

Selling Price (SP) = Original Price (OP) - Discount (D)

Discount (D) = Original Price (OP) * (D%/100)

Step 3:

Substitute given values in the formula

315 = OP - D

D = $OP \times30/100$

D = 0.3 OP

Step 4:

Substitute value of D in the first formula

315 = OP - 0.3 OP

315 = OP (1 - 0.3) = 0.7 OP

Original Price, OP = 315/0.7 = $450

5 0

4 years ago

If f(x)=x^3-12x^2+35x-24f(x)=x 3 −12x 2 +35x−24 and f(8)=0f(8)=0, then find all of the zeros of f(x)f(x) algebraically.

Neporo4naja [7]

Answer:

The zeros of f(x) are: (x - 1), (x - 3) and (x - 8)

Step-by-step explanation:

Given

$f(x)=x^3-12x^2+35x-24$

$f(8) = 0$

Required

Find all zeros of the f(x)

If $f(8) = 0$ then:

$x = 8$

And $x - 8$ is a factor

Divide f(x) by x - 8

$\frac{f(x)}{x - 8} = \frac{x^3-12x^2+35x-24}{x - 8}$

Expand the numerator

$\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 -8x^2 + 3x + 32x - 24}{x - 8}$

Rewrite as:

$\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 + 3x - 8x^2 +32x - 24}{x - 8}$

Factorize

$\frac{f(x)}{x - 8} = \frac{(x^2 - 4x + 3)(x - 8)}{x - 8}$

Expand

$\frac{f(x)}{x - 8} = \frac{(x^2 -x - 3x + 3)(x - 8)}{x - 8}$

Factorize

$\frac{f(x)}{x - 8} = \frac{(x - 1)(x - 3)(x - 8)}{x - 8}$

$\frac{f(x)}{x - 8} = (x - 1)(x - 3)$

Multiply both sides by x - 8

$f(x) = (x - 1)(x - 3)(x - 8)$

Hence, the zeros of f(x) are: (x - 1), (x - 3) and (x - 8)

7 0

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Inga [223]

Answer:

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Step-by-step explanation:

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