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lina2011 [118]
3 years ago
9

Express 233 base fouras a base six.​

Mathematics
1 answer:
ahrayia [7]3 years ago
3 0

Answer:

twenty one

Step-by-step explanation:

hhdhhdiejdihgeideseheeeiidgriuduurhidid

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PLEASE. HELP.
jekas [21]
I think the answer is A I’m not sure tho
6 0
3 years ago
Solve 2 log x = log 64. (1 point)
Vladimir79 [104]

Answer:

8

Step-by-step explanation:

2log(x)=log(64)

By logarithms properties

xlog_{a}(b)=log_{a}(b^{x} )  \\

log(x²)=log(64)

When you have log or ln in both sites, you delete them and...

x²=64

\sqrt[]{x^{2} } =\sqrt{64} \\x=8

7 0
3 years ago
PLs help me on this..........
Serggg [28]

Answer:

247277 people

Step-by-step explanation:

6% of 243,000 = 14,580

243,000 + 14,580 = 257,580

4% of 257,580 = 10,303.2

Estimating 10,303.2 to 10,303

257,580 - 10,303 = 247277

3 0
2 years ago
Read 2 more answers
Suppose 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea. Use a 0.05 significance
lana66690 [7]

Answer:

Null Hypothesis, H_0 : p = 0.20  

Alternate Hypothesis, H_a : p > 0.20  

Step-by-step explanation:

We are given that 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea.

We have to use a 0.05 significance level to test the claim that more than 20​% of users develop nausea.

<em>Let p = population proportion of users who develop nausea</em>

So, <u>Null Hypothesis,</u> H_0 : p = 0.20  

<u>Alternate Hypothesis</u>, H_a : p > 0.20  

Here, <u><em>null hypothesis</em></u> states that 20​% of users develop nausea.

And <u><em>alternate hypothesis</em></u> states that more than 20​% of users develop nausea.

The test statistics that would be used here is <u>One-sample z proportion</u> test statistics.

                     T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }   ~ N(0,1)

where,  \hat p = proportion of users who develop nausea in a sample of 241 subjects =  \frac{54}{241}  

             n = sample of subjects = 241

So, the above hypothesis would be appropriate to conduct the test.

6 0
3 years ago
Question 4. In the graph, lines f and g intersect at P(6,6). What is the area, in square units, of the shaded region? * E. 15 F.
erastova [34]

Answer:

E

Step-by-step explanation:

i guess the dotted lines outline a square

so get the area of the square which is 6×6=36

then don't focus on the shaded part but unshaded you'll see two right angled triangles

a = 1 \div2b \times h

you will get a total for both as 21

then get the area of the square 36-21=15

so the area becomes 15

3 0
3 years ago
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