Prove that the recurring decimal 0.39 = 13/33
1 answer:
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Answer:
B, C, and D.
Step-by-step explanation:
Let's go through each answer choice.
A: To find the slope of a line from two points, we use this formula: . Plugging in the values (-2,0) and (2, -4), we get:
Because option A says the slope is 1, but we got -1, option A is false.
B: To find the y-intercept, we use this formula:
Since we know the value of b is the y-intercept, we could write the y-intercept as (0,-2). Therefore, option B is true.
C: The equation of a line (in slope-intercept form) is y = mx + b, where y - y-coordinate, m = slope, x = x-coordinate, and b = y-intercept. Since we already solved for the y-intercept and slope, let's plug in those values:
As you can see, the equation we got here matches the one in option C, meaning it's true.
D: We know that a point is written like this: (x, y). If the x-coordinate is not zero but the y-coordinate is, then it's the x-intercept. Since the question says that (-2,0) is one of the points the line passes through, and option D says that the x-intercept is (-2,0), it's true.
The standard form of a quadratic equation is 
, while the vertex form is:
, where (h, k) is the vertex of the parabola.
What we want is to write
as
First, we note that all the three terms have a factor of 3, so we factorize it and write:
.
Second, we notice that
are the terms produced by 
, without the 9. So we can write:
, and substituting in we have:
![\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20y%3D3%28x%5E2-6x-2%29%3D3%5B%28x-3%29%5E2-9-2%5D%3D3%5B%28x-3%29%5E2-11%5D)
.
Finally, distributing 3 over the two terms in the brackets we have:
![y=3[x-3]^2-33](https://tex.z-dn.net/?f=y%3D3%5Bx-3%5D%5E2-33)
.
Answer:
What we want is to write
First, we note that all the three terms have a factor of 3, so we factorize it and write:
Second, we notice that
Finally, distributing 3 over the two terms in the brackets we have:
Answer: