Answer:
by stating what the time was before the zero point came.
Step-by-step explanation:
Gradient =(y1-y2) / (x1-x2)
(-6-8)/(6-8)
:7
y:mx+c
8:7(8)+c
c:-48
y:7x-48
F(x) = x^2 + 3x + 2
if g(x) is the reflection of f(x) across the x - axis then
g(x) = -f(x)
g(x) = - (x^2 + 3x + 2)
g(x) = - x^2 - 3x - 2
I think the answer is (2x - 9)(x - 5)
