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FrozenT [24]
2 years ago
8

PLEASE I NEED HELP CLICK ON THIS IMAGE

Mathematics
1 answer:
lesantik [10]2 years ago
6 0

Answer:

261

Step-by-step explanation:

I took each number and divided each of them by 9 until I got a whole number with no decimals.

261 ÷ 9 = 29

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the sides of a triangle have lengths s,s+4,and 3s write an expression that represents the perimeter of the triangle
mamaluj [8]
Perimeter of a poligon= sum of all sides.
Perimeter of this triangle=s+(s+4)+3s=5s+4

An expression that represents the perimeter of this triangle is:  5s+4
3 0
3 years ago
1.Which coordinates are not of the vertices of the feasible region for the system of inequalities?
astraxan [27]
2.   I think the answer is 24

subracting the last 2 inequalities we get

6x + 7y <= 42
3x + 2y  <= 18    subtract:_-
3x + 5y <= 24
3 0
3 years ago
I need help I don’t understand and I need to show my work who would help me??
stich3 [128]

Answer: b

Step-by-step explanation:

In the last question, you wrote on a second equation "13x ...." kkk

Let's go:

We have to check each one answer in the following system:

x - 2y = 7

3x + 7y = 8

I can use the substituition method to solve this system...

x = 7 + 2y

3x + 7y = 8

3(7 + 2y) + 7y = 8

21 + 6y + 7y = 8

13y = 8 - 21

13y = -13

y = -1

x = 7 + 2.(-1)

x = 5

Finally, the correct answer is the second one (letter b).

5 0
3 years ago
Read 2 more answers
what digit is in the ten thousands place 1.03098 which is the correct answer I know it's one of the zeros I believe which one is
elena-14-01-66 [18.8K]
Hello there

Actually, the correct answer is the 9

the first 0 is in the tenths spot, the 3 is in the hundredths, the second zero is in the thousandths, and the 9 is in the ten thousandths, while the 8 is in the hundred thousandths.

Therefore, the 9 is in the ten thousandths place

I hope this helped ^^ 
4 0
3 years ago
Location is known to affect the number, of a particular item, sold by an auto parts facility. Two different locations, A and B,
Mama L [17]

We have two samples, A and B, so we need to construct a 2 Samp T Int using this formula:

  • \displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}  }  

In order to use t*, we need to check conditions for using a t-distribution first.

  • Random for both samples -- NOT STATED in the problem ∴ <u><em>proceed with caution</em></u>!
  • Independence for both samples: 130 < all items sold at Location A; 180 < all items sold at Location B -- we can reasonably assume this is true
  • Normality: CLT is not met; <u>n < 30</u> for both locations A and B ∴ <u><em>proceed with caution</em></u>!

<u>Since 2/3 conditions aren't met, we can still proceed with the problem but keep in mind that the results will not be as accurate until more data is collected or more information is given in the problem.</u>

<u>Solve for t*:</u>

<u></u>

We need the <u>tail area </u>first.

  • \displaystyle \frac{1-.9}{2}= .05

Next we need the <u>degree of freedom</u>.

The degree of freedom can be found by subtracting the degree of freedom for A and B.

The general formula is df = n - 1.

  • df for A: 13 - 1 = 12
  • df for B: 18 - 1 = 17
  • df for A - B: |12 - 17| = 5

Use a calculator or a t-table to find the corresponding <u>t-score for df = 5 and tail area = .05</u>.

  • t* = -2.015

Now we can use the formula at the very top to construct a confidence interval for two sample means.

  • \overline {x}_A=39
  • s_A=8
  • n_A=13
  • \overline {x}_B = 55
  • s_B=2
  • n_B=18
  • t^{*}=-2.015

Substitute the variables into the formula: \displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}  }.

  • 39-55 \  \pm \ -2.015 \big{(}\sqrt{\frac{(8)^2}{13} +\frac{(2)^2}{18} } } \ \big{)}

Simplify this expression.

  • -16 \ \pm \ -2.015 (\sqrt{5.1453} \ )
  • -16 \ \pm \ 3.73139

Adding and subtracting 3.73139 to and from -16 gives us a confidence interval of:

  • (-20.5707,-11.4293)

If we want to <u>interpret</u> the confidence interval of (-20.5707, -11.4293), we can say...

<u><em>We are 90% confident that the interval from -20.5707 to -11.4293 holds the true mean of items sold at locations A and B.</em></u>

5 0
1 year ago
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