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Degger [83]
3 years ago
6

a water sprinkler sends water out in in a circle .how large is the watered area if the the watering Patten is 23 ft

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
3 0
I'm guessing you're saying that the sprinkler is shooting out 23 ft of water.

This would be the same as the radius of a circle, and we're trying to find the area. Use the formula.

\sf A=\pi r^2

Plug in what we know:

\sf A=\pi (23^2)

\sf A=529\pi ft^2

This is what they could be looking for, an exact value. If they want an approximation, we can input 3.14 for Pi:

\sf A\approx 529(3.14)

\boxed{\sf A\approx 1661.06~ft^2}
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An alligator population in a naturer preserve in the Everglades increased by 60 alligators or five years what is the mean yearly
adelina 88 [10]
I'm not sure what you meant after alligators, if it was or or for, but I think it was for so I'm going with that. If 60 increase every 5 years, it would be 60 over 5 (in fractions). So I would do 60 divided by 5, which would be 12. So that means 12 increase every year. I'm not sure what mean meant either, if you're talking about the mathematical mean, but you can't solve the mean in this problem. The Answer: The yearly change in the alligator population would be 12.
7 0
3 years ago
*In ∆ABC, on the extension of the side BC , draw a line segment CD ≅ CA . Draw the segment AD . The line segment CE is the angle
Leya [2.2K]

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Step-by-step explanation:

In ∆ABC

  • On the extension of the side BC , draw a line segment CD ≅ CA
  • Draw the segment AD
  • The line segment CE is the angle bisector of ∠ACB
  • The line segment CF is the median towards AD in ∆ ACD

We want to prove that CF ⊥ CE

Look to the attached figure

In Δ ABC

∵ CE is the bisector of angle ACB

∴ ∠ACE ≅ ∠BCE

In Δ ACD

∵ CA = CD

∴ Δ ACD is an isosceles triangle

∵ AD is the median towards AD

- In any isosceles triangle the median from a vertex to its opposite

  side bisects this vertex

∴ AD bisects ∠ACD

∴ ∠ACF ≅ ∠DCF

∵ BCD is a straight segment

∵ CE , CA , CF are drawn from point C

∴ m∠BCE + m∠ACE + m∠ACF + m∠DCF = 180°

∵ m∠ACE ≅ m∠BCE

∵ m∠ACF ≅ m∠DCF

- Replace m∠BCE by m∠ACE and m∠DCF by m∠ACF

∴ m∠ACE + m∠ACE + m∠ACF + m∠ACF = 180°

∴ 2 m∠ACE + 2 m∠ACF = 180°

- Divide all terms by 2

∴ m∠ACE + m∠ACF = 90°

∴ EC ⊥ CF

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Learn more:

You can learn more about perpendicular lines in brainly.com/question/11223427

#LearnwithBrainly

7 0
3 years ago
Plss help (ZOOM IN TO SEE FULL PIC)
shepuryov [24]

Answer:

H = 35

Step-by-step explanation

21 / 3 is 7 so multiply 7 by 5 to get 35. So 35 is equal to H.    

Plz Give 5 stars, Smash that thanks button and give brainlyest.

And don't forget having a bad day change it. Bye!

6 0
3 years ago
Can someone Solve this please !
pshichka [43]

Answer: What do I solve for?

Step-by-step explanation:

Do I need to solve for the slope, equation, x-int, etc?

7 0
1 year ago
Read 2 more answers
Carlos earns $8 per hour for the first 40 hours that he works during a week. He earns $12 an hour for every hour he works over 4
mash [69]

Answer:

Hi there!

Your answer is:

$440 earned from working a 50 hour week

Step-by-step explanation:

8× 40= $320

Subtract 40 from 50 to determine how many overtime hours he worked!

12× 10 = $120

320+ 120= $440

I hope this helps!

5 0
3 years ago
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