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Murljashka [212]
3 years ago
14

Which is NOT a way to solve 4÷15=n? Find out how many 1/5s are in 4.

Mathematics
1 answer:
ANTONII [103]3 years ago
4 0

Answer:

Solve 14×1/5=n  does not work

Step-by-step explanation:

Assuming you mean

4 ÷ 1/5=n


A Find out how many 1/5s are in 4.

That is correct.  We are writing the division problem in words


B Solve 4×5/1=n.

We can copy dot flip

4 * 1/5=n

C Solve 1/4×1/5=n.

We do not flip the first term

D Solve n×1/5=4.

4 ÷ 1/5=n

Multiply each side by 1/5

4 ÷ 1/5 * 1/5=n* 1/5

4 = n*1/5


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(a) [\frac{9}{2.6}  - \frac{2.5^{2} }{2.5} ]^{2}

Answer:

[\frac{9}{2.6}  - \frac{2.5^{2} }{2.5} ]^{2}

= [\frac{9}{2.6}  - \frac{2.5*2.5 }{2.5} ]^{2}

= [\frac{9}{2.6}  - \frac{2.5}{1} ]^{2}

*canceling 2.5 in numerator and denominator*

= [\frac{9-(2.5)(2.6)}{2.6} ]^2\\*Using L.C.M of 2.6 and 1 which comes out to be '2.6'= [\frac{9-(6.5)}{2.6} ]^2\\= [\frac{2.5}{2.6} ]^2\\*multiplying and dividing by '10'= [\frac{2.5*10}{2.6*10} ]^2\\= [\frac{25}{26} ]^2\\= \frac{25^2}{26^2}\\= \frac{625}{676}\\= 0.925

Properties used:

Cancellation property of fractions

Least Common Multiplier(LCM)

The least or smallest common multiple of any two or more given natural numbers are termed as LCM. For example, LCM of 10, 15, and 20 is 60.

(b) [[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3}    ] ^{2}

Answer:

[[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3}] ^{2}\\

*using [x^{a}]^b = x^{ab}*

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We can raise a power to a power

(x^2)4=(x⋅x)⋅(x⋅x)⋅(x⋅x)⋅(x⋅x)=x^8

This is called the power of a power property and says that to find a power of a power you just have to multiply the exponents.

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