The way you put it is confusing. I'll answer but the way you put it was confusing to me.
Answer is True. We cannot write it in rational form where both numbers are finite integers. In this case we cannot represent this number as fraction of finite integers therefore it is irrational.
we have
(a+b)(3a-b)(2a+7b)
step 1
Solve
apply distributive property
(a+b)(3a-b)=3a^2-ab-3ab-b^2=3a^2-4ab-b^2
step 2
Multiply (3a^2-4ab-b^2) by (2a+7b)
6a^3+21a^2b-8a^2b-28ab^2-2ab^2-7b^3=6a^3+13a^2b-30ab^2-7b^3
answer is
<h2>6a^3+13a^2b-30ab^2-7b^3</h2>
Answer:
5 faces
Step-by-step explanation:
4 triangle faces + 1 square base face = 5 faces in total
Answer:
C
Step-by-step explanation:
1. Identfiy The type therom it is which is alternate interior
2. Find the converse of the alternate interior which is the oppoiste so it has to be alternate exterior angle
