1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
arlik [135]
3 years ago
14

0.232 to the nearest tenth

Mathematics
2 answers:
nevsk [136]3 years ago
8 0
0.232 rounded to the nearest tenth
   ^
this is the tenths place 
so this would round to 0.2
bekas [8.4K]3 years ago
6 0
0.abc
a is tenth
look at thousandths place (b) to round
if b is more than or equal to 5, round b up 1
if b is less than 5 then ignore

0.232
b is 3
3<5
remain
0.2
You might be interested in
Solve the system.
Alex777 [14]

Answer:

{x,y,z} = {-18,4,2}

Step-by-step explanation:

Solve equation [2] for the variable  x  

x = -10y + 2z + 18

Plug this in for variable  x  in equation [1]

(-10y+2z+18) + 9y + z = 20

- y + 3z = 2

Plug this in for variable  x  in equation [3]

 3•(-10y+2z+18) + 27y + 2z = 58

   - 3y + 8z = 4

Solve equation [1] for the variable  y  

 y = 3z - 2

Plug this in for variable  y  in equation [3]

  - 3•(3z-2) + 8z = 4

   - z = -2

Solve equation [3] for the variable  z  

 z = 2

By now we know this much :

 x = -10y+2z+18

   y = 3z-2

   z = 2

Use the  z  value to solve for  y  

 y = 3(2)-2 = 4

Use the  y  and  z  values to solve for  x  

 x = -10(4)+2(2)+18 = -18

6 0
2 years ago
The length of time of the school field day was decreased
Tju [1.3M]
18% because take the first digits of each number and put them together lol
8 0
3 years ago
Andy bought 4 hamburgers snd 2 milkshakes for $13.50. Danny bought 3 hamburgers and 1 milkshake for $9.25. What cost of a hambur
Molodets [167]

A hamburger costs $2.5 and a milkshake costs $1.75

Step-by-step explanation:

  • Step 1: Form equations from the given details. Let cost of 1 hamburger be H and cost of 1 milkshake be M.

   4H + 2M = 13.50 ------ (1)

&  3H + 1M =   9.25 ------ (2)

  • Step 2: Multiply eq(2) with 2 to make coefficients of M equal.

   6H + 2M = 18.50 ------- (3)

  • Step 3: Subtract eq(3) from eq(1)

⇒ - 2H = - 5

⇒ H = $2.5

  • Step 4: Substitute value of H in eq(2) to find M.

⇒ 3 × 2.5 + M = 9.25

⇒ 7.5 + M = 9.25

⇒ M = $1.75

4 0
3 years ago
Express the sum of (square root) -64 and 3(square root) -4 as a monomial in terms of I.
Inga [223]
\bf \sqrt{-64}~+~3\sqrt{-4}\implies \sqrt{-1\cdot 2^6}~+~3\sqrt{-1\cdot 2^2}&#10;\\\\\\&#10;\sqrt{-1}\cdot \sqrt{2^6}~+~3\sqrt{-1}\cdot \sqrt{2^2}\implies i\cdot \sqrt{2^{3\cdot 2}}~+~3\cdot i\cdot 2&#10;\\\\\\&#10;i\cdot \sqrt{(2^3)^2}~~+~~6i\implies 2^3i~+~6i\implies 8i+6i\implies 14i
7 0
3 years ago
In triangle XYZ, shown above, what is the value of cos(X)?
adell [148]

Answer:

A

Step-by-step explanation:

Sine we can figure out side XY by using Pythagorean Theorem (A^2+B^2=C^2) and find that XY= 5, We can use Soh Cah Toa (The ways I remember to use value charts) and we know that Cosine uses Adjacent over Hypotenuse in which therefore the answer would be 5/13

8 0
3 years ago
Other questions:
  • Help please!!
    8·2 answers
  • Rename the number 4 thousand 7 hundreds
    15·2 answers
  • What is the slope of the line on the graph?
    15·1 answer
  • How many numbers are 3 units from 0 on the real numbers line
    14·2 answers
  • The time between seeing the lightning and hearing the thunder is s seconds. The distance d you are from lightning is approximate
    13·2 answers
  • ***please answer***
    14·1 answer
  • A wrestler is trying to gain weight for an upcoming match. His current weight is 105. In the formula shown, W = weight, p = poun
    12·2 answers
  • Which sequence is a geometric progression?<br> A 2 4 6 8<br> B 1 1 2 3<br> С 1 2 4 8<br> D 1 3 5 7
    7·1 answer
  • Find the area of this figure round your answer to the nearest hundredth. Use 3.14 to approximate
    11·1 answer
  • I need answer bahahhsbshana
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!