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s2008m [1.1K]
3 years ago
8

A map is drawn so that every 1 inch on the map represents 50 actual miles. The table below can be used to record the actual dist

ances between towns on the map.What is the actual distance between two towns that are 4 inches apart on the map?
Mathematics
1 answer:
olasank [31]3 years ago
7 0
200 miles
You just multiply 50 by 4.

:) have a good day !
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What are 5 decimals that are between 4.02 and 4.03
Xelga [282]
1) 4.021
2) 4.022
3) 4.023
4) 4.024
5) 4.025
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4 years ago
An art gallery sells paintings at $0.35 per square inch.If a painting is 2 feet 3 inches by 3 feet 5 inches, how much would the
Mamont248 [21]
The easiest way to solve this equation is to convert feet into inches, so lets just say the painting is 27 inches by 41 inches. 

Next multiply the two numbers 27*41=1107

Finally multiply 1107*.35= 387.45

The painting would cost $387.45
4 0
3 years ago
What's <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B11%20%5Ctimes%203%20%2B%203%7D%20" id="TexFormula1" title=" \sqrt{11 \
dolphi86 [110]

Answer:

<em>6</em><em> </em><em>Ans</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

Step-by-step explanation:

Data:

√11 x 3+3

Solution:

=√11 x 3+3

=√33+3

= <em>6</em><em> </em><em>A</em><em>n</em><em>s</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

5 0
3 years ago
A single 6-sided die is rolled. What is the probability of rolling a 2 or a 5? *
Shalnov [3]

Answer:

1/3

Step-by-step explanation:

4 0
3 years ago
Consider the expansion of (5p + 2q)^6. Determine the coefficients for the terms with the powers of p and q shown.
Step2247 [10]

Answer:

Remember, the expansion of (x+y)^n is (x+y)^n=\sum_{k=0}^n \binom{n}{k}x^{n-k}y^k, where \binom{n}{k}=\frac{n!}{(n-k)!k!}.

Then,

(5p+2q)^6=\sum_{k=0}^6\binom{6}{k}(5p)^{6-k}(2q)^k=\sum_{k=0}^6\binom{6}{k}5^{6-k}2^k p^{6-k}q^k

Then, the coefficient of the term p^{6-k}q^k is \binom{6}{k}5^{6-k}2^k

a) since 6-k=2, then k=4. So the coefficient of p^2q^4 is

\binom{6}{4}5^{6-4}2^4=15*5^2*2^4=15*25*16=6000

b) since 6-k=5, then k=1. So, the coefficient of p^5q is

\binom{6}{1}5^{6-1}2^1=6*5^5*2=37500

c) since 6-k=3, then k=3. So, the coefficient of p^3q^3 is

\binom{6}{3}5^{6-3}2^3=20*5^3*8=20000

6 0
3 years ago
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