Hey friend, hope I can assist you!
I will solve by elimination <3.
Multiply 3x - 7y = 2 by 2: 6x - 14y = 4
6x - 14y = 4
6x - 9y = 9
5y = 5
Now we have
6x - 14y = 4
5y = 5
Now we want to solve 5y = 5 for y
So simply divide both sides by 5.
5y/5 = 5/5
This gives us one or in other words, y = 1.
Now we want to plug y = 1 into 6x - 14y = 4
So 6x - 14 * 1 = 4
This gives us
6x - 14 = 4
Now add 14 to both sides.
6x - 14 + 14 = 4 + 14
6x = 18
Now divide both sides by 6
6x/6 = 18/6
This gives us 3 so x = 3
Therefore our solutions to this system of equations would be y = 1 and x = 3
There are 4 possibilities:
1) No event happens
2) event A happens, not event B
3) event B happens, not event A
4) both events happen
seeing as there is a 50% chance of either event happening, I would assume that all 4 possibilities have an equal chance of happening
so if there are 4 events, then each one is 25% likely.
So the probability if them both occurring is 25%
I think
Answer:
sorry if wrong put b as the answer
Answer:
what is the subject and grade please tell
Step-by-step explanation:
Just like you drew those dotted lines. You know how to find the areas of rectangles which is A=length x width
The answer would be 20cm^2+6cm^2+18cm^2=44 cm^2
