Answer:3.75 hours
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that L is a line parametrized by

The plane perpendicular to the line will have normal as this line and hence direction ratios of normal would be coefficient of t in x,y,z
i.e. (2,3,-1)
So equation of the plane would be of the form

Use the fact that the plane passes through (2,0,-1) and hence this point will satisfy this equation.

So equation is

b) Substitute general point of L in the plane to find the intersecting point

i.e. same point given.
Answer:
see explanation
Step-by-step explanation:
let ∠BCE = x then ∠ECD = 5x - 6 and
∠BCE + ∠ECD = ∠BCD, substitute values
x + 5x - 6 = 162, that is
6x - 6 = 162 ( add 6 to both sides )
6x = 168 ( divide both sides by 6 )
x = 28
Hence
∠BCE = x = 28°
∠ECD = 5x - 6 = (5 × 28) - 6 = 140 - 6 = 134°