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Ulleksa [173]
3 years ago
6

The cake store is having a 25%, percent off sale on all of its cakes. If the cake you want regularly costs $9 dollar , how much

would you save with the discount?
Mathematics
2 answers:
ivanzaharov [21]3 years ago
8 0
2.25$ because you must take your 9 dollar price and multiply it by the decimal 0.25 which stands for the 25% off

Irina-Kira [14]3 years ago
7 0
2.25 is how much you would save

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Min is about to roll a six-sided number cube. What is the probability that she will roll an even number? A) 1 4 B) 1 3 C) 1 2 D)
Irina-Kira [14]
P(e)=number of evens/number of numbers :)

P(e)=3/6=1/2
8 0
3 years ago
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How do you identify the necessary information that is missing from a problem?
alexdok [17]

Answer:

  It depends

Step-by-step explanation:

Identifying what is <em>not there</em> is always difficult. In the general case, the range of possibilities is infinite.

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6 0
3 years ago
F(x) = lnx/x
My name is Ann [436]
f(x) = \frac{lnx}{x}

(a) f'(x) = \frac{d}{dx}[\frac{lnx}{x}]
Using the quotient rule:
f'(x) = \frac{\frac{1}{x} \cdot x - lnx}{x^{2}}
f'(x) = \frac{1 - lnx}{x^{2}}

For maximum, f'(x) = 0;
\frac{1 - lnx}{x} = 0
lnx = 1, x = e

(b) <em>Deduce:
</em>e^{x} \geq x^{e}, x > 0
<em>
Soln:</em> Since x = e is the greatest value, then f(e) ≥ f(x) > f(0)
\frac{ln(e)}{e} \geq \frac{lnx}{x}
\frac{1}{e} \geq \frac{lnx}{x}, since ln(e) is simply equal to 1

Now, since x > 0, then we don't have to worry about flipping the signs when multiplying by x.
\frac{x}{e} \geq lnx
x \geq elnx
x \geq ln(x^{e})

Taking the exponential to both sides will cancel with the natural logarithmic function in the right hand side to produce:
e^{x} \geq e^{ln(x^{e}})
e^{x} \geq x^{e}, as required.
3 0
3 years ago
Those are 2 separate questions please help thank you.​
AysviL [449]

Answer:

the screen is really blurry and  its laying on its side for some reason

Step-by-step explanation:

8 0
3 years ago
What is 14.95 + 10% tip
Ostrovityanka [42]
16.445 I have no expectation sorry.
3 0
3 years ago
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