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Murljashka [212]
3 years ago
13

What is 4.86 divided by .2

Mathematics
2 answers:
stepan [7]3 years ago
8 0
Lets solve:







- - Solve for that to get answer:

24.3

Your final answer is 24.3

emmainna [20.7K]3 years ago
4 0
The answer of 4.68 by .2 is 23.4

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I will mark Brainliest!! 87 Points!!
DIA [1.3K]
<h3>f(x) = -3·2^(x-1) -1</h3>
  • reflection across the x-axis (multiplication by -1)
  • vertical expansion by a factor of 3 (multiplication by 3)
  • shift to the right 1 unit (replace x with x-1)
  • shift down 1 unit (add -1 to the function value)

_____

<h3>f(x) = -1/4·2^(x+1) -1</h3>

You may notice this is the same as the previous question, but with the vertical expansion factor 1/4 instead of 3, and the horizontal shift left instead of right.

  • reflection across the x-axis (multiplication by -1)
  • vertical compression by a factor of 4 (multiplication by 1/4)
  • shift to the left 1 unit (replace x with x+1)
  • shift down 1 unit (add -1 to the function value)

6 0
3 years ago
Read 2 more answers
Help pleassssssssssss
lara31 [8.8K]
A) The correct way to write 1/4 as a precent is 25%.

because....

1÷4= .25. and .25×100= 25%

b) The reporter most likely forgot to multiply by 100. The reporter instead just found what 1/4 was as a decimal, not a precent.
8 0
3 years ago
A gravel path is to be built around an 18‘ x 15‘ rectangle garden if the width remains constant how why can the path be if there
Ilia_Sergeevich [38]

Answer:

P = 2*(18 + 13) = 62ft

Now to figure out the width of the path we have to do some geometry. There are 3 basic shapes we will use for the path, they are the 13 ft long rectangle, the 18 ft long rectangle, and the squares formed at the corners. These squares' areas are equal to the width squared, whereas the rectangles are only equal to the length times the width. Our total area then becomes:

A = 2*(13*w) + 2*(18*w) + 4*(w*w)

A = 4w^2 + 62w

And since we know the available area is 516 ft^2, putting this in for A and solving the quadratic equation we can get the width:

516 = 4w^2 + 62w

0 = 4w^2 + 62w - 516

Using the quadratic formula: (w = -b2+/-SQRT(b^2 - 4ac)/2a, where a = 4, b = 62, and c = -516)

w = 6, -21.5

Since we obviously cannot have a negative width, 6 must be our answer. Therefore the path can be 6 feet wide!

We can check this answer by doing the following. Please note that by having a 6ft wide path you would actually be adding 12 ft to both dimensions, since you add 6 feet of length to both sides. Your total area would then become:

18+(2*6) x 13+(2*6) = 30x25 = 750 ft^2

Subtracting the area of the garden gives you the are of the gravel required:

750ft^2 - (18*13)ft^2 = 516ft^2

Therefore a width of 6 feet is correct.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A cylindrical tank of radius 5 ft and height 9 ft is two-thirds filled with water. Find the work required to pump all the water
Oduvanchick [21]

Answer:

130.826 kilojoules

Step-by-step explanation:

The Work required to pump water = pgV

Where, p = density of water = 1000 kg/m³

g = acceleration due to gravity = 9.81ms-¹

V = volume of water

Since, radius r = 5 ft and height h = 9ft

Volume of water in the cylindrical tank = (2/3)πr²h

V = (2/3)π *5²*9 = 471.24 ft³ = 471.24 * 0.0283m³ = 13.336m³

Work required = 1000*9.81*13.336

W = 130.826 KJ

Therefore, the work required to pump water 2/3 of the volume of the cylindrical tank = 130.826 kilojoules.

4 0
4 years ago
Please help me guys I’m tired
liberstina [14]
The slope is y=3x-7
a= y=3x-6 (or any number as long as the slope is same)
b = y=-1/3x -7
5 0
3 years ago
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