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3 years ago

Help plzzzzzzzzzzzzz

Mathematics

1 answer:

Snowcat [4.5K]3 years ago

5 0

Answer:

it is a reflection of point q

Step-by-step explanation:

they both are on different sides of the x axis

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Points U, M, And D are collinear with U between U and D.

zheka24 [161]

The value of x from the given equation is 5/3

<h3>How to determine the value</h3>

Since the three points are collinear to U, they are on a straight line which equals 0

Then we have,

UM + UD = MD

5x+30 + 10x+20 = 3x+80

Collect like terms

5x + 10x + 50 = 3x + 80

15x - 3x = 80 - 50

12x = 30

x = 30/12 = 15/6 = 5/3

Thus, the value of x from the given equation is 5/3

Learn more about collinear points here:

brainly.com/question/18559402

#SPJ1

5 0

2 years ago

PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER PLS GIVE ME A STEP BY STEP EXPLANATION!!

uysha [10]

Answer:

B) 9

Step-by-step explanation:

Quotient means that it’s for DIVISION. The 18 is the dividend, 2 is the divisor, and the quotient is the answer:

Dividend ÷ Divisor = Quotient

18 ÷ 2 = 9

3 0

2 years ago

Jack's father is three times older than Jack. Five years ago, the sum of their ages was 34. How old is Jack's father now?.

Allisa [31]

Answer:

jacks father is x

jack is 3x

34 =

5 0

2 years ago

What would the answer be for this equation 7x/20 - 5x/12

polet [3.4K]

Answer:

$\frac{1}{15} x$

Step-by-step explanation:

$\frac{7x}{20} - \frac{5x}{12}$

$\frac{3 \times 7x}{3 \times 20} - \frac{5 \times 5x}{5 \times 12}$

$\frac{21x}{60} - \frac{25x}{60}$

$\frac{21x - 25x}{60} = (21 - 25)x = - 4x$

$\frac{ - 4x}{60} = - \frac{ x}{15}$

$\boxed{\green{= \frac{1}{15} x}}$

4 0

2 years ago

Pumping stations deliver oil at the rate modeled by the function D, given by d of t equals the quotient of 5 times t and the qua

goblinko [34]

<h2>Hello!</h2>

The answer is: There is a total of 5.797 gallons pumped during the given period.

To solve this equation, we need to integrate the function at the given period (from t=0 to t=4)

The given function is:

$D(t)=\frac{5t}{1+3t}$

So, the integral will be:

$\int\limits^4_0 {\frac{5t}{1+3t}} \ dx$

So, integrating we have:

$\int\limits^4_0 {\frac{5t}{1+3t}} \ dt=5\int\limits^4_0 {\frac{t}{1+3t}} \ dx$

Performing a change of variable, we have:

$1+t=u\\du=1+3t=3dt\\x=\frac{u-1}{3}$

Then, substituting, we have:

$\frac{5}{3}*\frac{1}{3}\int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du\\\\\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u}{u} -\frac{1}{u } \ du$

$\frac{5}{9} \int\limits^4_0 {(\frac{u}{u} -\frac{1}{u } )\ du=\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u } )$

$\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u })\ du=\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du$

$\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du=\frac{5}{9} (u-lnu)/[0,4]$

Reverting the change of variable, we have:

$\frac{5}{9} (u-lnu)/[0,4]=\frac{5}{9}((1+3t)-ln(1+3t))/[0,4]$

Then, evaluating we have:

$\frac{5}{9}((1+3t)-ln(1+3t))[0,4]=(\frac{5}{9}((1+3(4)-ln(1+3(4)))-(\frac{5}{9}((1+3(0)-ln(1+3(0)))=\frac{5}{9}(10.435)-\frac{5}{9}(1)=5.797$

So, there is a total of 5.797 gallons pumped during the given period.

Have a nice day!

4 0

3 years ago