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alukav5142 [94]
3 years ago
5

Whats the square root of 39 to the nearest integer

Mathematics
2 answers:
soldi70 [24.7K]3 years ago
7 0

Answer:

To the nearest integer, the square root of 39 would be 6.

Step-by-step explanation:

To find the answer, look at the perfect squares on either side of 39. Lower than it would be 36 and the next highest would be 49. Since it is closer to 36, we can estimate that the answer is 6.

WINSTONCH [101]3 years ago
6 0

Answer:

6

Step-by-step explanation:

We can list the squares

1^2=1

2^2 =4

3^2 =9

4^2 = 16

5^2 =25

6^2 =36

7^2=49

39 is closest to 36  

sqrt(36) < sqrt(39) < sqrt(49)

6<sqrt(39) <7

39 is closer to 36 than 49 so it is closer to 6 than 7

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What is the slope of the line through (-5, -3) and (-5, -7)?
Paul [167]

Answer:

The answer is undefined.

Step-by-step explanation:

Slope is found using this equation: y-y1/x-x1. Fill in the coordinates to this equation. It should now look like this. -7--3/-5--5. When subtracting from two negatives, it changes into a positive. For example, -7--3 becomes -7+3, which equals -4. The same thing applies for the second part. -5--5 becomes -5+5, which equals 0. So, your slope is -4/0. However, when a 0 is in the denominator, it becomes undefined. So, the answer is undefined.

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3 years ago
Find the perimeter of the quadrilateral that has vertices at (8,13), (5,-18), (-6,-6), and (-2,-5).
kodGreya [7K]

Answer:

72.14 units

Step-by-step explanation:

Let A(8,13), B(5,-18),C(-6,-6) and D(-2,-5)

Apply the distance formula as;

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Finding the lengths of the segments

For AB

AB=\sqrt{(5-8)^2+(-18-13)^2} =\sqrt{(-3^2)+(-31^2)} =\sqrt{970} =31.14

For BC

BC=\sqrt{(-6-5)^2+(-6--18)^2} =\sqrt{(-11^2)+12^2} =\sqrt{265} =16.28

For CD

CD=\sqrt{(-2--6)^2+(-5--6)^2} =\sqrt{4^2+1^2} =\sqrt{16+1} =\sqrt{17} =4.12

For DA

DA=\sqrt{(8--2)^2+(13--5)^2} =\sqrt{10^2+18^2} =\sqrt{424} =20.6

Finding the perimeter will be;

31.14+16.28+4.12+20.6=72.14 units

3 0
3 years ago
You have a kite whose diagnoals are 8 m and 22 m. Find the area of the kite. Show all of your work.
Wittaler [7]
-----------------------------
Formula
-----------------------------
\text {Area of a kite = }  \dfrac{pq}{2}  \text { where p and q are the diagonals }

-----------------------------
Find Area
-----------------------------

\text {Area = }  \dfrac{8 \times 22}{2}

\text {Area = }  \dfrac{176}{2}

\text {Area = } 88 \  m^{2}

-----------------------------
Answer: Area = 88m²
-----------------------------
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Identify the distance between points (−3,−6,7) and (−9,5,−4), and identify the midpoint of the segment for which these are the e
melisa1 [442]

Step-by-step explanation:

LET THE Point 1 A and point 2 is B

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3 years ago
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