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3 years ago

The domain for f(x) and g(x) is the set of all real numbers. Let f(x) = 3x + 5 and g(x) = x2. Find g(x) − f(x).

Mathematics

1 answer:

kifflom [539]3 years ago

8 0

Answer:

3x^2 + 8

Step-by-step explanation:

Given functions,

f(x) = 3x + 8 ----(1)

g(x) = x^2 -----(2)

Since,

(fog)(x) = f( g(x) ) ( Composition of functions )

=f(x^2) ( From equation (2) )

=3x^2 + 8 ( From equation (1) )

Hence,

(fog)(x)=3x^2 + 8

Step-by-step explanation:

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Tammy made a 6-ounce milkshake. Two-thirds of the milkshake was ice cream. How many ounces of ice cream did

Alchen [17]

Answer: 4 ounces

Step-by-step explanation:

6 * (2/3) = 12/3 = 4 ounces

5 0

3 years ago

Use the given information to write an equation and solve the problem. (28-31 in the picture)

tia_tia [17]

Answer:

28. 120 degrees

29. 30 degrees

30. 56 degrees & 124 degrees

31. 72 degrees, 108 degrees, and 18 degrees

Step-by-step explanation:

We assign variable x for the answer we are looking for (28-29).

28.

Supplement means x + y = 180 degrees. We also know x = 2y. Substitution gives us 3y = 180 degrees, so y = 60 degrees and x = 120 degrees.

29.

Complement means x + y = 90 degrees. We are given 2x = y. Substitution brings us 3x = 90 degrees, x = 30 degrees.

30.

Supplement means x + y = 180 degrees. We are told that y = 2x + 12, so we substitute. This gives 3x + 12 = 180 degrees, x = 56 degrees. Substituting that back into the equation for y, we get 124 degrees.

31.

Supplement means x + y = 180 degrees. Complement means x + z = 90 degrees. Using our given info, we know y = 6z. We can substitute that in to get x + 6z = 180. Subtracting our second and third equations, we get 5z = 90, z = 18 degrees. Therefore, x = 72 degrees, y = 108 degrees.

3 0

2 years ago

Read 2 more answers

You and your friend are selling tickets to a charity event. You sell 11 adult tickets and 8 student tickets for $158. Your frien

svetlana [45]

So what we have to do to solve this problem is to write down those values in 2 equations (one that represents what you sold and the other what your friend sold) compare them and find how much each ticket is worth.
First equation : 11x + 8y = 158
Where x = how much each adult ticket is
and y = how much each student ticket is

The second equation is : 5x + 17y = 152

Using the method of substitution , we can compare each equation side by side:
11x + 8y = 158
5x + 17y = 152
Now we need to set one of the variables of both equations so they are equal:
11(5)x + 8(5) = 158(5)
5(11)x + 17(11)x = 152(11)

55x + 40y = 790
55x + 187y = 1672

Then we subtract the second equation by the first one

55x-55x + 187y - 40y = 1672 - 790
147y = 882
y = 6
The we apply y to one of the equations to discover x :
11x + 8y = 158
11x + 8(6) = 158
11x + 48 = 158
11x = 110
x = 10

So the awnser is :
Each adult ticket (x) is $10
And each student ticket (y) is $8
I hope you understood my explanation,

7 0

3 years ago

Read 2 more answers

A 100 gallon tank initially contains 100 gallons of sugar water at a concentration of 0.25 pounds of sugar per gallon suppose th

Vsevolod [243]

At the start, the tank contains

(0.25 lb/gal) * (100 gal) = 25 lb

of sugar. Let $S(t)$ be the amount of sugar in the tank at time $t$ . Then $S(0)=25$ .

Sugar is added to the tank at a rate of P lb/min, and removed at a rate of

$\left(1\frac{\rm gal}{\rm min}\right)\left(\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm gal}\right)=\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm min}$

and so the amount of sugar in the tank changes at a net rate according to the separable differential equation,

$\dfrac{\mathrm dS}{\mathrm dt}=P-\dfrac S{100}$

Separate variables, integrate, and solve for S.

$\dfrac{\mathrm dS}{P-\frac S{100}}=\mathrm dt$

$\displaystyle\int\dfrac{\mathrm dS}{P-\frac S{100}}=\int\mathrm dt$

$-100\ln\left|P-\dfrac S{100}\right|=t+C$

$\ln\left|P-\dfrac S{100}\right|=-100t-100C=C-100t$

$P-\dfrac S{100}=e^{C-100t}=e^Ce^{-100t}=Ce^{-100t}$

$\dfrac S{100}=P-Ce^{-100t}$

$S(t)=100P-100Ce^{-100t}=100P-Ce^{-100t}$

Use the initial value to solve for C :

$S(0)=25\implies 25=100P-C\implies C=100P-25$

$\implies S(t)=100P-(100P-25)e^{-100t}$

The solution is being drained at a constant rate of 1 gal/min; there will be 5 gal of solution remaining after time

$1000\,\mathrm{gal}+\left(-1\dfrac{\rm gal}{\rm min}\right)t=5\,\mathrm{gal}\implies t=995\,\mathrm{min}$

has passed. At this time, we want the tank to contain

(0.5 lb/gal) * (5 gal) = 2.5 lb

of sugar, so we pick P such that

$S(995)=100P-(100P-25)e^{-99,500}=2.5\implies\boxed{P\approx0.025}$

5 0

2 years ago

What is the equation of the line that is parallel to the line x = -2 and passes through the point (-5, 4)?

Nastasia [14]

Answer:

The equation of the line that is parallel to the line x = -2 and passes through the point (-5, 4) is x=-5

Option A is correct.

Step-by-step explanation:

We need to find equation of the line that is parallel to the line x = -2 and passes through the point (-5, 4)

We need a line parallel to x=-2 or x+2=0 it should be of form x+k=0

We need to find k, by putting value of x=-5 as given in question the point(-5,4)

-5+k=0

k=5

So, the equation of line will be found by putting k=5:

x+k=0

x+5=0

x=-5

So, the equation of the line that is parallel to the line x = -2 and passes through the point (-5, 4) is x=-5

Option A is correct.

8 0

2 years ago