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2 years ago

Determine a quadratic equation, in standard form, that has the pair of root: x=-3, x=5

Mathematics

2 answers:

vlabodo [156]2 years ago

6 0

Answer:

x²-2x-15=0

Step-by-step explanation:

x=-3 x=5

x+3=0 x-5=0

(x+3)(x-5)=0

x²-5x+3x-15=0

x²-2x-15=0

Mama L [17]2 years ago

5 0

Answer:

$x^2 -2x -15=0$

Step-by-step explanation:

$\text{Given that, the roots are,}~ \alpha=-3 ~ \text{and}~ \beta=5 .\\\\\text{The quadratic equation with roots}~ \alpha ~ \text{and}~ \beta ~ \text{is,}\\\\~~~~~~~~x^2 - (\alpha + \beta )x +\alpha \beta = 0\\\\\implies x^2-(-3 +5) x +(-3)(5) = 0\\\\\implies x^2 -2x -15=0$

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3 years ago

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Ksju [112]

Answer:

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