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Stels [109]
3 years ago
6

Clarice graphed the amount of money in her savings account during the past six months on the line graph.

Mathematics
2 answers:
Galina-37 [17]3 years ago
5 0

Answer:

Month 4 and 5

Step-by-step explanation:

This graph shows a very big increase in the change of the amt of money from 50 to 90 which is a 40 difference

N76 [4]3 years ago
4 0

Answer:

The answer to you question is months 4 and 5

Step-by-step explanation:

To solve this problem get the slope of the different intervals

2-3 Months      m = (80 - 110) / (3 - 2)

                              = -30 / 1

                              = -30

3 - 4 Months    m = (50 - 80) / (4 - 1)

                              = -30 / 1

                              = -30

4 - 5 Months     m = (90 - 50) / (5 - 1)

                               = 40 / 1

                               = 40

5 -6 Months       m = (110- 90) / (6 - 5)

                               = 20 / 1

                              = 20

Conclusion

The greatest change was between the months 4 and 5

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Step-by-step explanation:

Cube

A=6a^2=6*5^2=150cm^2

Triangular prism

Using these formulas

A=2A_{B}+(a+b+c)h\\A_{B} =\sqrt{s(s*a)(s*b)(s*c)} \\s=\frac{a+b+c}{2}

Solving for A

A=ah+bh+ch+\frac{1}{2} \sqrt{-a^4+2(ab)^2+2(ac)^2-b^4+2(bc)^2-c^4} \\=6.5*11+5*11+6.5*11+\frac{1}{2} *\sqrt{-6.5^4+2*(6.5*5)^2+2*(6.5*6.5)^2-5^4+2*(5*6.5)^2-6.5^4} \\=228ft^2

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2 years ago
Why is the percent increase from 45 to 75 not equal to the percent decrease from 75 to 452 Select three options
NNADVOKAT [17]

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Step-by-step explanation:

7 0
3 years ago
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jeyben [28]

Answer:

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3 0
3 years ago
Find the critical value of x2 based on the given information H1 >3.5 n=14 a=0.05
egoroff_w [7]

Answer:

The degrees of freedom are given by:

df = n-1=14-1=13

The significance level is \alpha=0.05 and then the critical value can be founded in th chi square table we need a quantile that accumulates 0.05 of the area in the right tail of the distribution and for this case is:

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And if the chi square statistic is higher than the critical value we can reject the null hypothesis in favor of the alternative.

Step-by-step explanation:

We have the followign system of hypothesis:

Null hypothesis: \sigma^2 \leq 3.5

Alternative hypothesis: \sigma^2 >3.5

The degrees of freedom are given by:

df = n-1=14-1=13

The significance level is \alpha=0.05 and then the critical value can be founded in th chi square table we need a quantile that accumulates 0.05 of the area in the right tail of the distribution and for this case is:

\chi^2_{\alpha}= 22.362

And if the chi square statistic is higher than the critical value we can reject the null hypothesis in favor of the alternative.

4 0
3 years ago
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