X^-1 = 1 / x ;
( x + 1 )^-1 = 1 / ( x + 1 ) ;
Then, x^-1 - ( x + 1 )^-1 = 1 / x - 1 / ( x + 1 ) = ( x + 1 ) / [x( x + 1 )] - x / [x( x + 1 )] = ( x + 1 - x ) /[x( x + 1 )] = 1 / [x( x + 1 )];
Finally, (1 / [x( x + 1 )])-2 =[x( x + 1 )]^2 = (x^2)[( x + 1 )^2] ;
Answer:
zero
Step-by-step explanation:
0.2 rounds down to 0
Answer:
0
Step-by-step explanation:5–3(x – 4)+2x. 5-34 + 12+2x. -X+17. (1.3) Solve the Linear Equation - Include Work! ... 2 = 10 -3-3. 7 - 3x=-3x+7. T infinitely many. 8x-3 =12x+10. -13=44. [x= -13%) ... x>-3 f x². > 15. -955 – 2x <7. 16. B +7== 5. 5. 5 a. -14 = 2 x 2. 1/3x+7=8. 3x=1 ... (x+90x+4)=0.
20{5[100-2(50)+20]}
20{5[100-100+20]}
20{5[20]}
20(100)
20000
