P-0.40p = 0.60p
C. Decrease by 40% is the same as multiply by 60%.
Assume that p = 10
10 - 0.40(10) = 0.60(10)
10 - 4 = 6
6 = 6
Based on the above assumption. 40% of 10 is 4 ; and 60% of 10 is 6. So, 10 less 4(40% of 10) is equal to 6 (60% of 10).
Percentage is used because 0.40 and 0.60 will be multiplied with 100% to get the equivalent percentage 0.40 x 100% = 40% ; 0.60 x 100% = 60%
Answer:
EH
Step-by-step explanation:
All you have to do is look at the order of the letters/segments and line them up. Like:
ABCD
EFGH
AB AND EF ARE PROPORTIONAL.
The average rates of change of f(x) and their corresponding intervals are given as:
Interval Rate of Change
[-5, -1] -8
[-4, -1] -7
[-3, 1] -4
[-2, 1] -3.
<h3>What is the explanation for the above?
</h3>
Step 1 - See Table Attached
Step 2 - State the formula for rate of change
The formula for rate of change is given as:
= [change in f(x)] / [change in x]
a) For interval [5, -1] ⇒
Rate of Change - [ f(1) - f(-5) ] / [-1 - (-5)]
= [-1 - 35] / [-1+5]
= -36 / 4
= - 8
b) For interval [-4, -1] ⇒
rate of change = [ f(-1) - f(-4) ] / [ -1 - (-4) ]
= [3 - 24] / [-1 + 4]
= -21/3
= - 7
c) interval [-3,1] ⇒
rate of change = [ f(1) - f(-3) ] / [ 1 - (-3) ]
= [-1 - 15] / [1 + 3]
= -16/4
= - 4
d) interval [-2,1] ⇒
rate of change = [f (1) - f(-2)] / [1 - (-2)]
= [ -1 - 8] / [1 + 2]
= -9/3
= -3
Learn more about rate of change at:
brainly.com/question/25184007
#SPJ1
Problem 1
Answer: Independent
The reason why is because each bag is separate from one another, so one event doesn't affect the other. If we know the result of what we pulled out of one bag, it doesn't change the probability of the other event.
======================================
Problem 2
Answer: Dependent
Assuming you do not put the first card back, then the probability of picking a King on the second draw will be different than if you picked a King on the first draw. With all 52 cards in the deck, the probability of getting a king is 4/52 = 1/13. It changes to 4/51 after we picked out an ace for the first card (and didn't put that first card back).
