Answer:
d = 200 miles
t = 1.5 hrs after start
Step-by-step explanation:
Set the origin at car a starting point.
equation for distance to car b
x = 250 - 60t
equation for distance to car a
y = 80t
distance between car a and car b
d = √((250 - 60t)² + (80t)²)
d = √(62500 - 30000t + 3600t² + 6400t²)
d = √(62500 - 30000t + 10000t²)
d = 100√(6.25 - 3t + t²)
setting the derivative to zero
0 = 100t - 150 / √(t² - 3t - 6.25)
The denominator cannot be zero, so the numerator must
0 = 100t - 150
150 = 100t
t = 1.5 hrs
d = √((250 - 60(1.5))² + (80(1.5))²)
d = √(160² + 120²)
d = 200 miles
Answer:
The coordinates of 
are 
and 
.
Step-by-step explanation:
Let be 
and 
endpoints of segment AB and a point located 7/10 the way from A to B. Vectorially, we get this formula:
By Linear Algebra we get the location of :
If we know that 
and 
, then:
The coordinates of are and .
The number is 175
greater than 100 less than 200, 10-5=5, 5+2=7
1 7 5
----- ----- -----
It is 7 cuz u - 2 and add 5 and 2-6=4+5=9-2=7
Answer:
C
Step-by-step explanation:
m1 and m2 are adjacent angles on a straight line, hence have the sum 180.
