Answer:
$12,000.
Step-by-step explanation:
Given that in the year 2001, a person bought a new car for $ 15500, and for each consecutive year after that, the value of the car depreciated by 5%, to determine how much would the car be worth in the year 2005, to the nearest hundred dollars, the following calculation must be performed:
100-5 = 95
15,500 x 0.95 x 0.95 x 0.95 x 0.95 x 0.95 = X
14.725 x 0.95 x 0.95 x 0.95 x 0.95 = X
13,988.75 x 0.95 x 0.95 x 0.95 = X
13,289.3125 x 0.95 x 0.95 = X
12,624.846875 x 0.95 = X
11.993.60453125 = X
Thus, to the nearest hundred dollars, the cost of the car after 5 years will be $ 12,000.
Answer:
x ≈ - 0.14
Step-by-step explanation:
6(4x + 5) = 3(x + 8) + 3 ← distribute parenthesis on both sides
24x + 30 = 3x + 24 + 3 , simplify
24x + 30 = 3x + 27 ( subtract 3x from both sides )
21x + 30 = 27 ( subtract 30 from both sides )
21x = - 3 ( divide both sides by 21 )
x =
= -
≈ - 0.14 ( to the nearest hundredth )
Answer:
The container can hold 22 gallons of water.
Step-by-step explanation:
Let 'g' be the number of gallons a container can hold
- Given the initial amount of water = 1/6 g
Given that 11 gallons of water have been added to the container.
- so the final quantity will become = 2/3 g
Thus, the equation becomes

Multiply by LCM 6



Divide both sides by 3


Therefore, the container can hold 22 gallons of water.
Answer:Using point slope intercept form