If x∆y = 3x - y², then
5∆1 = 3×5 - 1² = 15 - 1 = 14
and
14∆6 = 3×14 - 6² = 42 - 36 = 6
So (5∆1)∆6 = 6.
3w +2 =7w
-3w -3w
2=4w
Divide each side by 4
1/2=w
Check your answer:
3 (1/2) + 2 = 7 (1/2)
(3/2) + (4/2) = (7/2)
(7/2) = (7/2)
Hope this helps.
Answer:
Most likely wrong but i thinkkk C
Step-by-step explanation:
Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]
the area of each trapezoid is (v(t1)+v(t2))/2 times width
for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8
2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24
3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75
4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7
add them all up
0.8+2.24+1.75+0.7=5.49
5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
