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Katyanochek1 [597]
3 years ago
6

How to write 3,897.003 in expanded form

Mathematics
1 answer:
alexdok [17]3 years ago
8 0
3,000 + 800 + 90 + 7 + .003 = 3,897.003
Hope this helps!!!:)
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What is the distance between the points (-4,2) and (3,-5)
34kurt

Answer:

7√2 units

Step-by-step explanation:

The distance between two points having coordinates (x1, y1) and (x2, y2) is given by,

\sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} }

Here, x1=-4 and y1=2

x2=3 and y2=-5

\sqrt{ {(3  - ( -  4))}^{2}  +  {( - 5 - 2)}^{2} }

\sqrt{ {(3 + 4)}^{2}  +  {( - 7)}^{2} }

\sqrt{ {(7)}^{2}  +  {( - 7)}^{2} }

\sqrt{49 + 49}  = 7 \sqrt{2}

6 0
3 years ago
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Suppose f(x) = x^2. What is the graph of g(x) =f(4x)?
Alika [10]

Answer:

your y-intercept is 0 and slope is 4 so any line with zero slope it will be horizontal

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3 years ago
How would I do the steps to solve this?
allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

R(p) = -10p^2+800p

Taking derivative wrt p

\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\

Now putting R'(p) = 0

-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000

The maximum revenue is 16000 dollars (at p = 40)

3 0
2 years ago
Alan buys 5.2 ounces of sour patch kids candy. After sharing with his friends he returns to buy an additional 6.75 ounces. How m
Ainat [17]
11.95 ounces

5.2 + 6.75 = 11.95
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3 years ago
Show the work on how to answer -3|x|=-24
nignag [31]

Answer:

x=8  x=-8

Step-by-step explanation:

-3|x|=-24

Divide each side by -3

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There are 2 solutions a positive and a negative

x=8  x=-8

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3 years ago
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