If a toy rocket is launched vertically upward from ground level with an initial velocity of 128 ft per second, then its height h
after t seconds is given by the equation h(t) = -16t ^2 + 128t. What is the height after 60 seconds?
2 answers:
Answer:
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Step-by-step explanation:
t=60 is outside the domain of the function, which is t ∈ [0, 8].
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If you take the function and the time at face value, ...
... h(60) = -49920 . . . feet, more than 9.4 miles below ground level*
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*The deepest hole ever drilled into the Earth is 40,230 feet deep, so this is almost 2 miles deeper.
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The surface are of the right cone is 176 sq.units. Option A) is the correct answer.
<u>Step-by-step explanation</u>:
<u>step 1</u> :
Radius of the cone, <em>r = 4</em>
Height or length of the cone,<em> h = 10</em>
<u>step 2</u> :
Total surface area of right cone = πrh + πr^2
= (π4
10) + ( π
4^2)
= 40π + 16π
= 56 π = 563.14
= 176 sq.units