If a toy rocket is launched vertically upward from ground level with an initial velocity of 128 ft per second, then its height h
after t seconds is given by the equation h(t) = -16t ^2 + 128t. What is the height after 60 seconds?
2 answers:
Answer:
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Step-by-step explanation:
t=60 is outside the domain of the function, which is t ∈ [0, 8].
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If you take the function and the time at face value, ...
... h(60) = -49920 . . . feet, more than 9.4 miles below ground level*
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*The deepest hole ever drilled into the Earth is 40,230 feet deep, so this is almost 2 miles deeper.
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Answer:
9.
10.
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Answer:
The maximum height is reached after 3.75 seconds.
Step-by-step explanation:
Assuming the deceleration due to gravity is unaided by air resistance, gravity causes the ball to lose vertical speed at the rate of 32 ft/s every second. The initial vertical speed of 120 ft/s will decline to zero when t satisfies ...
... 120 ft/s - (32 ft/s²)t = 0
... (120 ft/s)/(32 ft/s²) = t = 3.75 s
The ball will not go any higher after its vertical speed is zero.
