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dalvyx [7]
2 years ago
12

If a toy rocket is launched vertically upward from ground level with an initial velocity of 128 ft per second, then its height h

after t seconds is given by the equation h(t) = -16t ^2 + 128t. What is the height after 60 seconds?

Mathematics
2 answers:
Rufina [12.5K]2 years ago
4 0

Answer:

undefined

Step-by-step explanation:

t=60 is outside the domain of the function, which is t ∈ [0, 8].

_____

If you take the function and the time at face value, ...

... h(60) = -49920 . . . feet, more than 9.4 miles below ground level*

___

*The deepest hole ever drilled into the Earth is 40,230 feet deep, so this is almost 2 miles deeper.

KengaRu [80]2 years ago
3 0

Answer:

C) 8 seconds

Step-by-step explanation:

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2 years ago
NEED HELP ASAP!!
Solnce55 [7]

Answer:

Only Cory is correct

Step-by-step explanation:

The gravitational pull of the Earth on a person or object is given by Newton's law of gravitation as follows;

F =G\times \dfrac{M \cdot m}{r^{2}}

Where;

G = The universal gravitational constant

M = The mass of one object

m = The mass of the other object

r = The distance between the centers of the two objects

For the gravitational pull of the Earth on a person, when the person is standing on the Earth's surface, r = R = The radius of the Earth ≈ 6,371 km

Therefore, for an astronaut in the international Space Station, r = 6,800 km

The ratio of the gravitational pull on the surface of the Earth, F₁, and the gravitational pull on an astronaut at the international space station, F₂, is therefore given as follows;

\dfrac{F_1}{F_2} = \dfrac{ \dfrac{M \cdot m}{R^{2}}}{\dfrac{M \cdot m}{r^{2}}} = \dfrac{r^2}{R^2}  = \dfrac{(6,800 \ km)^2}{(6,371 \ km)^2} \approx  1.14

∴ F₁ ≈ 1.14 × F₂

F₂ ≈ 0.8778 × F₁

Therefore, the gravitational pull on the astronaut by virtue of the distance from the center of the Earth, F₂ is approximately 88% of the gravitational pull on a person of similar mass on Earth

However, the International Space Station is moving in its orbit around the Earth at an orbiting speed enough to prevent the Space Station from falling to the Earth such that the Space Station falls around the Earth because of the curved shape of the gravitational attraction, such that the astronaut are constantly falling (similar to falling from height) and appear not to experience gravity

Therefore, Cory is correct, the astronauts in the International Space Station, 6,800 km from the Earth's center, are not too far to experience gravity.

6 0
3 years ago
The odds in favor of jim beating a friend at golf are 1:8. find the probability that jim will win.
agasfer [191]

The probability that jim will win = P(A) = 1/9

<h3>What is  probability?</h3>

The area of mathematics known as probability deals with numerical descriptions of how likely it is for an event to happen or for a claim to be true. A number between 0 and 1 is the probability of an event, where, broadly speaking, 0 denotes the event's impossibility and 1 denotes its certainty.

<h3>According to the given information :</h3>

The odds in favor of jim beating a friend at golf are =  1:8

Let A be the event that Jim beating a friend golf.

So,

according to ratio, it becomes

P(A)/P(A') = 1/8

P(A) = 1x

P(A')  = 8x

we know that :

P(A) + P(A') = 1

x + 8x = 1

9x = 1

x = 1/9

so that

P(A) = 1/9

P(A')  = 8/9

the probability that jim will win = P(A) = 1/9

To know more about probability visit:

brainly.com/question/10735118

#SPJ4

3 0
1 year ago
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