If a toy rocket is launched vertically upward from ground level with an initial velocity of 128 ft per second, then its height h
after t seconds is given by the equation h(t) = -16t ^2 + 128t. What is the height after 60 seconds?
2 answers:
Answer:
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Step-by-step explanation:
t=60 is outside the domain of the function, which is t ∈ [0, 8].
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If you take the function and the time at face value, ...
... h(60) = -49920 . . . feet, more than 9.4 miles below ground level*
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*The deepest hole ever drilled into the Earth is 40,230 feet deep, so this is almost 2 miles deeper.
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Answer:
y=x-3
Step-by-step explanation:
Graph y=x-5 and the point (1,-2). You want your slope to be the same for the lines to be parallel. The slope in the given equation is 1/1. Type into a graphing calculator y=x- and pick a number greater than negative five since the point (1,-2) is above the given line. Guess and checking reveals -3 to be the correct answer. Therefore, your answer is y=x-3.
