4 years ago

Step by step PLEASE!!!

1 answer:

7 0

F(x) = 3x^2+6x-2

= 3(x^2+2x-2/3)
= 3(x^2 +2x + 1 - 1 - 2/3)
= 3((x+1)^2 - 1 - 2/3)
= 3((x+1)^2 -5/3))
= 3(x+1)^2 - 5

So our function is in the form:

f(x) = 3(x+1)^2 - 5
where a = 3, h = -1, k = -5

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