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riadik2000 [5.3K]
3 years ago
10

Tim enlarged a picture with a width of 5.5 inches and a length of 8 inches by a scale factor of 3. What are the dimensions of th

e enlargement?
a. width: 24 in.; length: 16.5 in.b. width: 16.5 in.; length: 24 in.c. width: 14.5 in.; length: 22 in.d. width: 19.5 in.; length: 25 in.
Mathematics
2 answers:
olasank [31]3 years ago
8 0
It is B. 8*3 = 24. 5.5*3 = 16.5
Alekssandra [29.7K]3 years ago
3 0

Answer:

Option b. width = 16.5 inches and length = 24 inches

Step-by-step explanation:

Tim enlarged a picture wit a width of 5.5 inches and a length of 8 inches.

He enlarged the picture by a scale factor of 3.

We have to find the new dimensions of the picture.

Since, New dimension of the picture = Scale factor × dimensions before enlargement

So new width = 3×5.5 = 16.5 inches

new length = 3×8 = 24 inches

Therefore, option b. is the answer.

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Help help help help help
sdas [7]

Draw out a number line with the values 0, 5, 10, 15, 20, 25, 30, etc (basically multiples of 5)

Then plot a point at 25

-----------------

Or you can draw out a number line with the multiples of 10, so with the values 0, 10, 20, 30, ...

Then plot a point at the exact midway point between 20 and 30 to represent the value 25

3 0
4 years ago
Draw a function of dy/dx for the graphical below (image). Please help!
fenix001 [56]

Step-by-step explanation:

Remember that

\frac{dy}{dx}

is the gradient or slope function.

So we need to analyze the slope of each graph over given time.l and how it changes.

For the 1st graph, we have a linear function.

Remember the special properties for all linear functions:

The slope at any two points on the line is the same.

So this means our slope here must be constant.

And since our slope is negative, our dy/dx, function must be a constant function that is negative. So

The answer for the first graph is draw a horizontal line underneath the x axis.

For the 2nd graph, we have a slope that is decreasing, reaches 0 at the minimum, then increases even more.

We can draw a linear function that is increasing forever for our dy/dx.

For the 3rd graph, we are increasing , till we hit 0, then decrease until we hit 0, then forever increases.

Our dy/dx will be a parabola that passes through the x axis twice at two different points, facing upwards.

The first , second, and third graph is the dy/dx graphs shown respectively.

All these are examples of possible graphs. If you need more clarification, let me know

4 0
2 years ago
PLEASE HELP ME IF YOU CAN ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Reil [10]

Answer:

The maximum is at (0,4)

Step-by-step explanation:

x≥0

y≥0

x+y ≤4

2x+y ≤6

We need to plot the four inequalities.  The left side has no axis.  The max is at 4.  The minimum is at 0  for the shaded area

When we have a system of constraints, the minimum and maximum are at the vertices of the graph

There are 4 points

(0,0)

The intersection point of the 2 lines which is (2,2)

The intersection at the y axis (0,4)

The intersection at the x axis is (3,0)

Once we have these points we put them into the constraint equation

C = 30x+50y

(0,0)

C = 0+0 = 0  This would be the trivial point since nothing happens

(0,4)

C = 0+50(4) = 200

(3,0)

C = 30*3 = 90

(2,2)

C = 30(2) + 50(2) = 60+100 = 160

The maximum is at (0,4)

3 0
3 years ago
Evaluate ( z^2 + 4 ) ( z^2 – 5)
Kitty [74]

Answer:

z^4-z²-20

Step-by-step explanation:

( z^2 + 4 ) ( z^2 – 5)

z^4+4z²-5z²-20

z^4-z²-20

3 0
3 years ago
Please Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
alekssr [168]
Anything smaller than 0.75 would work, such as 0.25
3 0
4 years ago
Read 2 more answers
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