(8v + s)5 (multiply 5 into the parentheses)
(8v × 5) + (s × 5)
40v + 5s
Solving a polynomial inequation
Solving the following inequation:
(x - 8) (x + 1) > 0
We are going to find the sign both parts of the multiplication,
(x - 8) and (x + 1), have when
x < - 8
-8 < x < 1
1 < x
Then we know (x - 8) (x + 1) > 0 whenever (x - 8) (x + 1) is positive
We can see in the figure (x - 8) (x + 1) is positive when x < -8 and x > 1
Then
Answer:B
Answer:
the third one ( -7+u+8t)
Step-by-step explanation:
first you add the ts together and you get 8. Then u keep the U and cancel out the +2 nad the -2. Then you are left with your answer. have a nice day
Step-by-step explanation:
false
4^0 + 5^0 + 6^0= 1+1+1=3
(4+5+6)^0= 3⁰=1
1≠3