Answer:
4 & 8 = Corresponding Angles | 6 & 7 = Linear Pair | 1 & 3 = Vertical Angles | 2 & 8 = Alternate Interior Angles
Step-by-step explanation:
Answer:
y=1x-4
Wait sorry I did it wrong the first time lol.
In standard Form, it should be 4x-4y=16
Step-by-step explanation:
yes yes hand me brain
Answer:
![(ab)(x)](https://tex.z-dn.net/?f=%28ab%29%28x%29)
Step-by-step explanation:
If
and
then
A.
![(ab)(x)=(2x-4)(x+2)=2(x-2)(x+2)=2(x^2-4)=2x^2-8](https://tex.z-dn.net/?f=%28ab%29%28x%29%3D%282x-4%29%28x%2B2%29%3D2%28x-2%29%28x%2B2%29%3D2%28x%5E2-4%29%3D2x%5E2-8)
B.
![\dfrac{a}{b}(x)=\dfrac{2x-4}{x+2}](https://tex.z-dn.net/?f=%5Cdfrac%7Ba%7D%7Bb%7D%28x%29%3D%5Cdfrac%7B2x-4%7D%7Bx%2B2%7D)
C.
![(a-b)(x)=(2x-4)-(x+2)=2x-4-x-2=x-6](https://tex.z-dn.net/?f=%28a-b%29%28x%29%3D%282x-4%29-%28x%2B2%29%3D2x-4-x-2%3Dx-6)
D.
![(a+b)(x)=(2x-4)+(x+2)=2x-4+x+2=3x-2](https://tex.z-dn.net/?f=%28a%2Bb%29%28x%29%3D%282x-4%29%2B%28x%2B2%29%3D2x-4%2Bx%2B2%3D3x-2)
The only quadratic function appears in option A.
The equation for a parabola can also be written in the "vertex form":
y = a (x - h) ^ 2 + k
In this equation, the vertex of the parabola is the point (h, k).
We have then:
y = 2x2 + 16x + 17
We look for the vertice:
0 = 4x + 16
x = -16 / 4
x = -4
Substituting:
y = 2 * (- 4) ^ 2 + 16 * (- 4) +17
y = -15
Substituting the given point:
y = 2 (x +4) ^ 2 - 15
Answer:
y = 2 (x +4) ^ 2 - 15
option C
Answer:
c, if wrong sorry and plz don't die!!!
Step-by-step explanation: