Answer:
Step-by-step explanation:
On the day of the canteen, 800 coupons were sold, the price of each coupon was RM 30 and RM 50 respectively. The amount of money earned from the sale of coupons was RM30000. How many copies of RM30 and RM50 coupons were sold?
Let:
RM 30 = x
RM 50 = y
x + y = 800 - - - (1)
30x + 50y = 30000 - - - (2)
From (1)
x = 800 - y
Put x = 800 - y in (2)
30(800 - y) + 50y = 30000
24000 - 30y + 50y = 30000
24000 + 20y = 30000
20y = 30000 - 24000
20y = 6000
y =
Answer:
Im sorry for you this is too complex
He would have to sell at least 19 vacuums.
x y
1 16
2 12
3 8
5 0
Step-by-step explanation:
you have to substitute ever number on the X side in the equation to get the Y
for example 1 is under x so you will take
y=20-4(1)
y=20-4
y=16
Answer:
Repost your picture; it is super blurry.
Step-by-step explanation:
